If I understand the logic correctly . . . # imports import pandas as pd from io import StringIO # sample data s1 = “””id Name score 111 Jack 2.17 112 Nick 1.11 113 Zoe 4.12″”” s2 = “””id Name score 111 Jack 2.17 112 Sick 1.10 113 Zoe 4.12 114 Jay 12.3″”” df1 = … Read more
You could use enumerate to iterate over the indices and values. Then use next to stop upon finding the first non-zero value. If StopIteration was thrown, the list contained no non-zero values, so do whatever error handling you’d like there. def first_non_zero(values): try: return next(idx for idx, value in enumerate(values) if value != 0) except … Read more
You selected the correct regexp, you just have to quote it to use it in Python. You also need to call re.findall(), it’s not a string method. import re txt=”I refer to https://google.com and i never refer http://www.baidu.com” print(re.findall(r'(?<=https:\/\/)([A-Za-z0-9.]*)’, txt)) 1 solved Which of the following regular expressions can be used to get the domain … Read more
The terminating condition a + b <= i is equivalent to b <= i – a which in turn (as Python for uses less than not less than or equal) would be b < i – a + 1. That means in Python you could write: for b in range((i – a) / 2, i … Read more
I think this is what you’re after: file = open(“demo.txt”,”r”) text = file.read() def find(info,text): match = re.findall(info + “+\w+\d+”,text) if match: print(match) else: print(“Not found!”) # This is how you call the function find(“whatever info is supposed to be”,text) 3 solved python Regular expression [closed]
here you go : s = “test” chk = reduce(lambda a,b : a^b, [ord(c) for c in s]) print “Checksum : “, chk, ” \n” sh-4.3$ python main.py Checksum : 22 0 solved Need help for checksum on python
You were pretty close: import itertools l = [1,2,3,4,5,6] ts = 8 def psl(l, ts): for i in range(len(l)): for c in itertools.combinations(l, i): if sum(c) == ts: print list(c) psl(l, ts) solved Print all combinations of list that sum to a number [closed]
Thank you everyone, the code I found to be the answer was this: begin = int(input(‘Enter begin: ‘)) end = int(input(‘Enter end: ‘)) palindromes = palindromes = len([i for i in range(begin, end+1) if str(i) == str(i)[::-1]]) for i in range(begin, end+1): if str(i) == str(i)[::-1]: print(i,’is a palindrome’) print(‘There are’, palindromes, ‘palindrome(s) between’, begin, … Read more
input takes only a single string, so to concatenate instead of cake_amnt = int(input(‘How many’,cake,’would you like to make?’)) You should use format to build the string cake_amnt = int(input(‘How many {} would you like to make?’.format(cake))) Or use the + operator to perform concatenation cake_amnt = int(input(‘How many ‘ + cake + ‘ would … Read more
Add a print(N) line after all the N+= lines, and try various Z arrays. For example Define a small z with a block of 1s in the middle: In [29]: z = np.zeros((10,10),int) In [31]: z[4:6,4:6]=1 In [34]: z[4:8,5]=1 In [35]: z Out[35]: array([[0, 0, 0, 0, 0, 0, 0, 0, 0, 0], [0, 0, … Read more
You can’t make win32api.SendMessage() non-blocking because the underlying Windows function is blocking. Instead you can use win32api.PostMessage(), it has the same signature: import win32api, win32con print “start” win32api.PostMessage(win32con.HWND_BROADCAST, win32con.WM_SYSCOMMAND, win32con.SC_MONITORPOWER, 2) print “end” 3 solved How to make SendMessage unblocking?
As already mentionned, you cannot (at least not out of the box and not without huge pain) directly embed Python code in an Django template, and as far as I’m concerned that’s a GoodThing(tm) – the “server page” model (PHP, ASP1 etc) has long proven to be a failure wrt/ maintainability. Now for the good … Read more
a = [[0, 1], [0, 1, 2], [0, 1, 2, 3]] print ‘\n’.join([‘\t’.join([str(x[i]) if len(x) > i else ” for x in a]) for i in range(len(max(a)))]) #0 0 0 #1 1 1 # 2 2 # 3 1 solved How to vertically print 2d list with different lengths in python
No, Python supports more collection types. You missed the tuple, the deq, the string and bytes for example. Actually the possibilities are infinite since you can make any object a collection by implementing some special methods and also you can subclass most built-in sequence times. solved Does Python include only 3 collection types?
You can use binascii.hexlify(): In [25]: strs=b’\x0f\x00\x00\x00NR09G05164\x00′ In [26]: import binascii In [27]: binascii.hexlify(strs) Out[27]: b’0f0000004e52303947303531363400′ 3 solved Python : convert a hex string