[Solved] Finding smaller numbers in an array
I would first start with sorting the list using b_sorted=sorted(b) solved Finding smaller numbers in an array
I would first start with sorting the list using b_sorted=sorted(b) solved Finding smaller numbers in an array
You can do: old_list = [ [‘ID 1d6b:0002’], [‘ID 1d6b:0002’], [‘ID 1d6b:0001’], [‘ID 1d6b:0001’], [‘ID 1d6b:0001’], [‘ID 1d6b:0001’], [‘ID 1d6b:0001’], [‘ID 0b38:0010’], [‘ID 093a:2510’]] new_list = [x[0] for x in old_list] This uses list comprehension to create a new list that contains the first elements ([0]) all on the lists in the old list. Hope … Read more
You’ve used the same name, list, for both a built-in type and a local variable. Don’t re-use the built-in names. Quoting PEP-8: If a function argument’s name clashes with a reserved keyword, it is generally better to append a single trailing underscore rather than use an abbreviation or spelling corruption. Thus class_ is better than … Read more
from itertools import combinations, permutations perm=[] index = [9,7,6,5,2,10,8,4,3,1] perm.append(index) M = 3 slicer = [x for x in combinations(range(1, len(index)), M – 1)] slicer = [(0,) + x + (len(index),) for x in slicer] result = [tuple(p[s[i]:s[i + 1]] for i in range(len(s) – 1)) for s in slicer for p in perm] 1 … Read more
The reason you have the error is because the lists made by glob and os.listdir are not the same, either different files (glob is only getting jpg files and listdir gets everything) or different order, or both. You can change the filenames in a list, orig_files, to make a corresponding list of new filenames, new_files. … Read more
This will work. List splicing is what you’re after. def yesterday(): for i in range(1,len(“yesterday”)+1): print(“yesterday”[:i]) yesterday() solved Python 3.7 new line and slicing [closed]
First, remove ! by using str.replace() and then split the string using str.split(). line=”a but tuba!” line = line.replace(‘!’, ”).split(‘ ‘) print line Output: [‘a’, ‘but’, ‘tuba’] solved How do I split multiple characters without using any imported libraries?
I have rewrote your code a little bit and it works now: from selenium import webdriver from getpass import getpass from selenium.webdriver.support.ui import WebDriverWait from selenium.webdriver.common.by import By from selenium.webdriver.support import expected_conditions as EC chromedriver = “C:\\Users\\Utente\\Desktop\\chromedriver” driver = webdriver.Chrome(chromedriver) usr = input (“Enter Your Email: “) psw = getpass(“Enter Your Password: “) prfl = … Read more
You can use the indices method of the slice to generate a tuple that can be passed to range. You need to know the length of your instance though. For example: >>> sl = slice(2) # or wherever you get that from >>> length = 100 >>> list(range(*sl.indices(length))) [0, 1] 5 solved How to transform … Read more
Here’s a straightforward solution with a simple loop: dict_x = {} for value in list_x: if isinstance(value, str): dict_x[value] = current_list = [] else: current_list.append(value) Basically, if the value is a string then a new empty list is added to the dict, and if it’s a list, it’s appended to the previous list. solved Convert … Read more
You need to specify the newline character when you open the file. On Windows, the default ends up adding an extra ‘\r’. with open(‘quotes.csv’, ‘a’, newline=”\n”) as myFile: writer = csv.DictWriter(myFile, fieldnames=fieldnames) … 1 solved i don’t know why this code is writing empty rows on my csv file when using a PC but not … Read more
As others said, you should call sqrt() only with proper values. So better do … #Check discriminant discrim = float((bval**2)-(4*aval*cval)) if float(discrim >= 0): # now it is ok to calculate the roots… root1 = – bval + math.sqrt(discrim) root2 = – bval – math.sqrt(discrim) if float(discrim > 0): print (“Roots at:”, root1, root2) else: … Read more
Variables in Python are just references. I recommend making a copy by using a slice. l_copy = l_orig[:] When I first saw the question (pre-edit), I didn’t see any code, so I did not have the context. It looks like you’re copying the reference to that row. (Meaning it actually points to the sub-lists in … Read more
Try looking at the diff function in numpy. That will give you the difference between each value and its right neighbor. You can then check if that value is smaller or larger than 0. 0 solved Python check if one value is greater than the next one in array/vector [duplicate]
Additional lines include a vertical line, a horizontal line, a line connecting two or more pairs of dates and prices, and a trend line. Here is an example of simply drawing a line with date and price. Please refer to this page for more details. import datetime import pandas as pd import pandas_datareader.data as web … Read more