You could just slice the list: mainlist = [5,4,3,2,1] n = 3 mainlist, mylist= a[:n], a[n:] Keep in mind that for slicing, the first index is inclusive, while the second is exclusive, so mainlist wouldn’t contain index 3 but mylist would. 4 solved In Python how do you pop the first n elements of a … Read more
I found some info in link below.solution Using wmi classes we can take info from our monitors, then for each monitor takes values from fields and write it to file. $Monitors = Get-WmiObject WmiMonitorID -Namespace root\wmi $LogFile = “d:\monitors.txt” “Manufacturer,Name,Serial” | Out-File $LogFile ForEach ($Monitor in $Monitors) { $Manufacturer = ($Monitor.ManufacturerName|where {$_ -ne 0}|ForEach{[char]$_}) -join … Read more
I think you need empty list so you can append the numbers to that i.e FirstNumbers = [1, 2, 3] SecondNumbers = [4, 5, 6] ThirdNumbers = [7, 8, 9] NestedNumbers = [FirstNumbers, SecondNumbers, ThirdNumbers] m = [] for i in range(0, 3): k = [] for each_number in NestedNumbers: k.append(each_number[i]) m.append(k) Output m : … Read more
Add all of your variables to a list and then you can use the max function like so max(lista) num1 = int(input(‘What is the first number?: ‘)) num2 = int(input(‘What is the second number?: ‘)) num3 = int(input(‘What is the third number?: ‘)) lista = [num1, num2, num3] biggest = max(lista) print(f”{biggest} is the largest … Read more
You might want to use use zip functionality to print pairs of values. list1 = [“1”, “2”] list2 = [“3”, “4”] for pair in zip(list1, list2): print i This will print: (‘1’, ‘3’) (‘2’, ‘4’) Please notice that the lists should be at the same size. 2 solved Print a single string from and an … Read more
You must realize that 12 does not divide 52, and that there are not 4 weeks to every month. So to give an example that you can fine tune to get exactly what you want, I’ve defined a week to belong to the same month that its thursdays belong to. This dovetails nicely with the … Read more
Why do you populate the Player object with ‘magic’ shouldn’t is be Person = Player(200, 100, 60, 40, magic) Otherwise it would be interpreted as string. 1 solved String indices must be integers (error) when accessing dictionary [closed]
Basically np.random.randn returns random float values of normal distributions with mean = 0 and variance = 1. Now np.random.randn takes shape you would like to return of those distributions. For example: np.random.randn(1,2) returns an array of one row and two columns. Similarly, you can give np.random.randn(1,.,.,.,9) which gives you out a complicated array. Since you … Read more
This is actually very well described in most tutorials; the general rule is: a and b is b if a is true, else it is a; a or b is a if a is true, else it is b. Now, False, None, (), [], {}, ”, 0 and 0.0 are all considered false; practically everything … Read more
i found “locals” which could meet my needs: getVar = locals() a1 = “a1” a2 = “a2” a3 = “a3” bb1 = [a1,a2] bb2 = [a1,a2,a3] all_sql = [bb1,bb2] for one in all_sql: db_values = “,”.join([str([getVar[i]) for i in all_sql]) db.exec_insert(db_values) my unclear expression and poor English may troubled others 🙁 solved Python: is there … Read more
You should do the following: generate a string containing all the letters use ranodm.sample() instead of random.choice() to generate a list of 3 random letters, which you then should join() return an in-place list with the new elements It’d look like this: import string import random def add_str(lst): _letters = string.ascii_letters return [”.join(random.sample(set(_letters), 3)) + … Read more
difflib‘s SequenceMatcher does exactly what I wanted. s = difflib.SequenceMatcher(None, result, correct) s.ratio() solved Find difference of two String lists – Python
Thanks Eric Duminil For Print A Solution. a=input(“Let me do an operation: “) print (eval(a)) 1 solved Can python calculate more than 2 input numbers?
The for loop actually does loop, it just does do anything unless the answer is correct. you want: while enter!=”off”: if enter == “1”: prefer= input(“enter your preference”) if prefer ==”sports”: print(“Hardcore Sports Podcast”) enter = input(‘Enter 1 – recommendation, 2 – draw, off – exit’) else: print(“Kanye West’s new album”) enter = input(‘Enter 1 … Read more
You only return something when if sinRep == dondeborrar fails and then during the loop if(sinRep == sinRep_AUX) succeeds. You can solve these problems by moving the return statement to the end of the function. def elimina_Rep(dondeborrar, cantidadNecesaria, fichcompleto): sinRep = [] # Donde almacenaremos las NO repetidas sinRep_AUX = [] # Para borrar en … Read more