[ad_1] The Runge-Kutta methods need to advance in small steps, 5 is not a small step. Try setting N to 1000.0 instead (the decimal is to make sure that (b-a)/N != 0). [ad_2] solved Overflow error in Python program
[ad_1] Define you connection as below: import sqlite3 conn = sqlite3.connect(‘musicten.db’) 2 [ad_2] solved creating database based on two dataframes
[ad_1] Suppose we have 2 list x = [‘3’, ‘1’] y = [‘1’, ‘3’] Solution-1: You can simply check whether the multisets with the elements of x and y are equal: import collections collections.Counter(x) == collections.Counter(y) This requires the elements to be hashable; runtime will be in O(n), where n is the size of the … Read more
[ad_1] itertools.izip_longest takes an optional fillvalue argument that provides the value that is used after the shorter list has been exhausted. fillvalue defaults to None, giving the behaviour you show in your question, but you can specify a different value to get the behaviour you want: fill = a[-1] if (len(a) < len(b)) else b[-1] … Read more
[ad_1] You probably meant to write a * (a//b). Multiplication happens before division, since it’s on the left and has same priority. [ad_2] solved a * a//b doesn’t work properly in Python (// Operator)
[ad_1] The .upper() and .lower() functions do not modify the original str. Per the documentation, For .upper(): str.upper() Return a copy of the string with all the cased characters converted to uppercase. For .lower(): str.lower() Return a copy of the string with all the cased characters converted to lowercase. So if you want the uppercase … Read more
[ad_1] First, try using a dict() to store the mappings. Lots easier. mymappings = dict() def add_mapping( l1, l2): mymappings[l1] = l2 mymappings[l2] = l1 add_mapping(‘a’,’e’) add_mapping(‘b’,’z’) … word = None while word != ”: word = raw_input(“Word:”) print ”.join( [mymappings[x] for x in word if mymappings.has_key(x)] ) Then just do a list comprehension on … Read more
[ad_1] It’s hard to do for a specific pixel area, but you could get the HTTP response body (e.g. the HTML of the web page you want) by making an HTTP request to the website and reading the response. You can do that with Python’s httplib package. Then parse the response, e.g. using an XML … Read more
[ad_1] Like stated in the comments: put the relevant code in the try clause, and raise a specific exception. You can prompt again with a loop. Something like this: succeeded = False while not succeeded: try: aws_account = input(“Enter the name of the AWS account you’ll be working in: “) session = boto3.Session(profile_name=aws_account) client = … Read more
[ad_1] I’ve got the needed outcome using following script. XML File: <?xml version=”1.0″ encoding=”UTF-8″?> <base> <element1>element 1</element1> <element2>element 2</element2> <element3> <subElement3>subElement 3</subElement3> </element3> </base> Python code: import pandas as pd from lxml import etree data = “C:/Path/test.xml” tree = etree.parse(data) lstKey = [] lstValue = [] for p in tree.iter() : lstKey.append(tree.getpath(p).replace(“https://stackoverflow.com/”,”.”)[1:]) lstValue.append(p.text) df = … Read more
[ad_1] In an Ipython session I can do: In [2]: %load_ext Cython In [3]: one = 1 In [4]: %%cython …: def foo(num): …: return num + 1 …: In [5]: foo(one) Out[5]: 2 That is I define a cython function, but call it from Python with the global variable. If I define the function … Read more
[ad_1] This is not a valid python code, u are missing braces. Here : data = { u’entities’: { u’symbols’: [], u’user_mentions’: [], u’hashtags’: [{u’indices’: [3, 13], u’text’: u’firstpost’}, {u’indices’: [22, 35], u’text’: u’snowinginnyc’}], u’urls’: [{u’url’: u’https://t.co/0sClwIMXKW’, u’indices’: [36, 59], u’expanded_url’: u’https://vine.co/v/hQPlQ9l5XDD’, u’display_url’: u’vine.co/v/hQPlQ9l5XDD’} ] } } and print data[‘entities’][‘urls’][0][‘expanded_url’] prints vine.co/v/hQPlQ9l5XDD [ad_2] solved Python … Read more
[ad_1] You need to indent your code properly: import os for x in os.listdir(“/home/”): print x 3 [ad_2] solved Python list contents error [duplicate]
[ad_1] The distance from one vertical edge to another is either from the right-hand side of rect1 to the left-hand side of rect2, or the other way around. You don’t need to know which rectangle is the one on the left or right; you can take the smaller of the two possible values. rect1 = … Read more
[ad_1] Long story short, the Pi is too complex hardware-wise to operate without an OS (for the vast majority of tasks, anyway). An operating system is essentially an environment for your program to work in. It provides standardized means to use and manage hardware, interrupts, storage (incl. filesystems), I/O etc. What is more inportant, it … Read more