[Solved] How to open a file in python 3

open creates a stream of data associated with the file. It does not initiate a file viewing software. os.startfile(‘path/to/file.ext’) # opens file in respective program 10 solved How to open a file in python 3

[Solved] Assign user_str with a string from user input, with the prompt: ‘Enter a string:\n’ user_str = int(input(‘Enter a string:\n’) print(user_str)

Assign user_str with a string from user input, with the prompt: ‘Enter a string:\n’ user_str = int(input(‘Enter a string:\n’) print(user_str) solved Assign user_str with a string from user input, with the prompt: ‘Enter a string:\n’ user_str = int(input(‘Enter a string:\n’) print(user_str)

[Solved] intersection of two or more lists of dicts

You can convert the list of dicts to set of tuples of dict items so that you can use functools.reduce to perform set.intersection on all the sets, and then convert the resulting sequence of sets to a list of dicts by mapping the sequence to the dict constructor: from functools import reduce def intersection(*lists): return … Read more

[Solved] Count consecutive spaces(&nbsp) at the start of the string in Python [closed]

The most pythonic way to do this is the following: def count_start_spaces(s): return len(s) – len(s.lstrip()) Given the following input: strings = [“Test1 False (String 1)”,” Test2 False (String 2)”,” Test3 False (String 3)”] list(map(count_start_space, strings)) # output: [0, 4, 8] 2 solved Count consecutive spaces(&nbsp) at the start of the string in Python [closed]

[Solved] How to locate an element and extract required text with Selenium and Python

You can use driver.find_element_by_css_selector(‘.form-control + [for=address]’).text Use replace() to remove the enter this code: string if required That is a class selector “.” with adjacent sibling combinator joining to attribute = value selector. So element with attribute for having value address that is adjacent to element with class form-control. solved How to locate an element … Read more

[Solved] Replace [1-2] in to 1 in Python

You could use a regex like: ^(.*)\[([0-9]+).*?\](.*)$ and replace it with: $1$2$3 Here’s what the regex does: ^ matches the beginning of the string(.*) matches any character any amount of times, and is also the first capture group\[ matches the character [ literally([0-9]+) matches any number 1 or more times, and is also the second … Read more