$sep = ‘ยป’; $parents = get_category_parents( $cat, TRUE, $sep ); $parents = explode( $sep, trim( $parents, $sep ) ); if( 1 === count( $parents ) ) { /* No category parents. */ require_once ( get_template_directory() . ‘/category-parent.php’ ); } else { /* One or more parent categories. */ require_once ( get_template_directory() . ‘/category-child.php’ ); } … Read more
Change this; $query=mysql_query(“select * from users where userId=’$uname’ and pwd =’$pwd’ “); to: $query=mysql_query(“SELECT * FROM users WHERE pwd =’$pwd’ AND (userId = ‘$uname’ OR PhoneNum = ‘$uname’)”); What this does it will take both $uname value and search both Userid column and Phone Num column for a match. Please note that PhoneNum is the … Read more
You have two options: Save data (in a file, in mysql…) Grab the data every time a user loads the page (check every page for news) Of course it is better to save the data in some way, but it is possible to do it without a database or similar. You have to realize that … Read more
Your question is a little unclear, but if you’re trying to pass an array using a single form input the short answer is no, using a single element you cannot pass an array into the POST array (with the exception of the multi-select form element), but it’s easy with a tiny bit of processing once … Read more
Try echo date(‘Y-m-d’, strtotime(‘Monday this week’)); echo date(‘Y-m-d’, strtotime(‘Sunday this week’)); 2 solved Week of the day for current date in php [closed]
Why you used the php CURL to http request. You can use the laravel HTTP client. You can see: https://laravel.com/docs/8.x/http-client#making-requests 1 solved Get data from URL using PHP
Without knowing your full requirements, this should get you started. I imagine you are going to want to store the saved/changed text into a database. If this is the case, you need to build upon what is provided below. Hope this helps. Enter Text Here… <?php if( isset( $_POST[‘my_text’], $_POST[‘save’] ) && strlen( $_POST[‘my_text’] ) … Read more
Use this. here I use userId to select a particular row. you can alter it or not use it according to your requirement. $query = “SELECT amount FROM table1 WHERE userId='{$id}'”; $result = mysqli_query($con,$query); $sql = “UPDATE table2 SET total=”{$result}” WHERE userId='{$id}'”; mysqli_query($con,$sql); 0 solved i want to transfer data from column to another table … Read more
$id = $array[‘id’]; unset($array[‘id’]); foreach($array as $k=>$v) { $array[$k][‘id’] = $id; } solved Arranging array in a proper format [closed]
You’ve given very little in the way of details. I’ll provide an answer here that’s as simple as possible: Use SSD If you’re not already using SSD that’s probably the issue. Conventional hard drives are terrible at random I/O and will bog down on occasion when too busy to service requests in a timely manner. … Read more
convert it into json and try it. hope that works for you. 4 solved how to pass array in ajax call using php
Basically, you read the file to variable, then fill with value of this variable, and then on form submit update DB value with one from textarea. Though, you have to watch encoding changes or text can be screwed. For exact functions, as it is PHP, you can look at http://www.php.net/manual/en/ , it has nice search, … Read more
This is actually a pretty easy feature to add to a chat. You are first going to need a place to store the typing information. I usually just store it in a database. 1 for is typing, and 0 for not. You are going to want to use a smart setup so that when typing … Read more
If you want a flat iteration of a directory structure, try combining the RecursiveDirectoryIterator drived by RecursiveIteratorIterator. This is how the skeleton of the iteration could look like: $start_dir=”/some/path”; $rit = new RecursiveIteratorIterator( new RecursiveDirectoryIterator( $start_dir, FilesystemIterator::KEY_AS_PATHNAME | FilesystemIterator::CURRENT_AS_FILEINFO | FilesystemIterator::SKIP_DOTS ), RecursiveIteratorIterator::SELF_FIRST ); foreach ($rit as $path => $fileinfo) { $level = $rit->getDepth(); if … Read more
$var=”something”; $$var=”lol”; echo $something will output “lol” it’s a variable variable. solved what is a variable with two $ sign ? $$ myVar [duplicate]