[ad_1] JSON is not HTML. You cannot have a <head> element in a JSON file. It makes the JSON invalid, so it cannot be parsed. [ad_2] solved Ask about server send json and client receiver for process [php] not work when server have tag ?
[ad_1] You get this notice because array $_POST does not have first_name key like another ones. They are going to appeared only when you make POST request like submit the form or make AJAX call. 1. One file for GET and POST request. In your snippet I can see you have one *.php file for … Read more
[ad_1] You can’t use IF as a statement in a query, it can only be used in a stored procedure. To do what you want, you need two separate queries. Try this: $del_query = “DELETE FROM favoritebills WHERE userid = ‘$userid’ and billid = ‘$billid'”; $ins_query = “INSERT INTO favoritebills (userid,billid) VALUES($userid,$billid) “; $res = … Read more
[ad_1] Looks like the query is actually pulling 3 results as it should. You are just letting one of them go: function adminnav (){ $pagewcoms = mysql_query(…); // HERE YOU FETCH ONE ROW BUT DO NOTHING WITH IT $idnavrow = mysql_fetch_row($pagewcoms); while ($itest = mysql_fetch_row($pagewcoms)) { echo “$itest[0] <br />”; } } If you just … Read more
[ad_1] This should do the trick: <?php function hash_data($data) { $data = mb_convert_encoding($data, ‘UTF-16LE’, ‘UTF-8’); $hash = hash(‘sha512’, $data, true); return base64_encode($hash); } $user=”admin”; $password = ‘secret’; $key = “7f9facc418f74439c5e9709832;0ab8a5:OCOdN5Wl,q8SLIQz8i|8agmu¬s13Q7ZXyno/yv.XSN1DsgKq9zi]XrE^gx8vPC^Av8=e/bF4pX1Oe hfqGb#JK~RONkS1wx5w=RE0$” . “DxZSu7evPfshBw7p5Gb&suEkw=RE0DxZSu7e´vPfshBw7p+5GbsuEkw=H1fTWFXfsXo}z0fOd{KTt[IdDG2y6E=”; $data = $user . $password . $key; // 6xecArT38JVtGKH2yQs/T6btOUF41vW5ptaPjgrd8hTaZZKnbJed5551LuYV7vR/Dr3Jb873JMvX0je+8XUpxw== echo hash_data($data); [ad_2] solved How I can convert this function to php?
[ad_1] Your query() call returns false as it’s failed. That’s why fetchAll can’t be executed. Debug your query! (I think it’s a typo error and tite should be title) 0 [ad_2] solved php Error – Call to a member function fetchAll() on boolean [duplicate]
[ad_1] Situation before: $citylink_view = “view=$targetview&postevent=$_GET[postevent]”; which is the same as: $citylink_view = “view=$targetview&postevent=” . $_GET[‘postevent’]; Which can be written as: $foo = $_GET[‘postevent’]; $citylink_view = “view=$targetview&postevent=” $foo; You wrote: $posteventview = $_GET[‘postevent’]; $citylink_view = “view=$targetview&”.$posteventview; Can you spot the difference? Aside, you are possible vulnerable to XSS. Sanitize the input and urlencode. Use filter_* … Read more
[ad_1] Thumb Rule: Any dom manipulation done using JavaScript will not be visible in the view source. 1 [ad_2] solved Meta tag is not showing in page view source, that added using jquery [closed]
[ad_1] This is almost a duplicate of: How to restructure multi-dimensional array with columns as rows? and Combining array inside multidimensional array with same key This can be done with foreach loops, but I like the condensed variadic method (PHP 5.6+). You can research the aforementioned links to see the other techniques if your version … Read more
[ad_1] $date = “2017-12-31”; echo date(“Y-m-d”, strtotime($date . ” +5 days”)); Strtotime() can translate some sentences to actions. See example 1 [ad_2] solved Add +1 or more day to DATETIME in php eaven if that day is in a different month [closed]
[ad_1] For Linux operating system you have to set the default apache user and group in its configuration file. That is apache2.conf Steps 1. vim /etc/apache2/apache2.conf 2. set user and group to your machine account user and group 3. then save it 4. then restart apache (service apache2 restart) For example User vijay Group vijay … Read more
[ad_1] That is perfectly safe, if that is your question, since php as a quasi interpreted language does not leave any traces or artifacts when terminating the execution. If it is a good practice is another thing. I’d say it is fine for testing purposes, but you should avoid it in final code. Reason is … Read more
[ad_1] Here is your solution…. <script src=”https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js”></script>//jQuery Plugin <?php if(!empty($_GET[‘a1’])){ $selected = $_GET[‘a1’];} else{ $selected = ‘home’;} ?> <form action=”” method=”post”> <label> <input type=”radio” name=”a1″ value=”home” /> Home </label></br> <label> <input type=”radio” name=”a1″ value=”site1″ /> Site 1 </label></br> <label> <input type=”radio” name=”a1″ value=”site2″ /> Site 2 </label></br> </form> <span class=”r-text”><?php echo $selected;?></span> <script> $(‘input[type=radio]’).click(function(e) {//jQuery … Read more
[ad_1] header(“Location: login.php”); is called after you send content (maybe an error in your includes), you should put this one before any showed contents. I see you do that : echo $Nama; It’s the kind of thing that makes a headers already sent by error… 2 [ad_2] solved Cannot modify header information – headers already … Read more
[ad_1] Loop through it using a foreach statement and append it to another array. $finished = []; foreach($array as $arr) { $finished[$arr->id] = $arr->organisation; } [ad_2] solved converting array of objects to simple array [closed]