You can’t overload operator== for C strings, because they are pointers and operators can be overloaded if at least one operand is a class or enum. What you can do is create your own comparator function and use it in your code instead of ==: template<typename T> bool my_equal(const T& a, const T& b) { … Read more
What does no match for ‘operator>>’ (operand types are ‘std::istream’ {aka ‘std::basic_istream’} and ‘float*’) mean? [closed] solved What does no match for ‘operator>>’ (operand types are ‘std::istream’ {aka ‘std::basic_istream‘} and ‘float*’) mean? [closed]
Func f();, it prints nothing, it should print Constructor That is not true whatsoever. Here is how you create a Func: Func f; When I try to use operator() f(2) it gives me compilation error. error C2660: ‘f’ : function does not take 1 arguments. Isn’t it strange behaviour or I am missing something? Yes, … Read more
there is no custom operator overloading in java. [so you cannot overload it to call equals()] the equals() ensures you check if 2 Objects are identical,while == checks if this is the exact same object. [so no, using == does not invoke equals()]. 2 solved Comparing java Strings with == [duplicate]
First I assume you have some basics that look like this #include <iostream> struct vec2 { double x; double y; }; std::ostream& operator<<(std::ostream& stream, vec2 v2) {return stream<<v2.x<<‘,'<<v2.y;} //real methods vec2 translate(vec2 in, double a) {return vec2{in.x+a, in.y+a};} //dummy placeholder implementations vec2 rotate(vec2 in, double a) {return vec2{in.x+1, in.y-1};} vec2 scale(vec2 in, double a) {return … Read more
Issue with: template <typename T> bool operator== (const String<T>& a, const String<T>& b ) is the deduction of T, and for “hello” == String<char>(“hello”), “hello” doesn’t match const String<T>&, so that overload is discarded. What you can do is to make it non template: template <typename T> class String { // non template function. friend … Read more