[ad_1] This should solve your problem: mod <- survreg((Surv(as.numeric(Time), event=Status)) ~ Prison+Dose+Clinic, data = meth, dist = “lognormal”) as you reported to me that: names(meth) # [1] “ID” “Clinic” “Status” “Time” “Prison” “Dose” Note, it is Time, not time; Also, it is Status, not status. In fact, all variables names start with a capital letter! … Read more
[ad_1] you should aggregate by column and then sum the results, try this: Notice that, the patient name should should have a numerical counter for keeping track. import pandas as pd import datetime import numpy as np # this a dummy set, you should have already this in your data frame dict_df = {‘Patient’: [1,2,3,4,5], … Read more
[ad_1] EDIT#1: If the value ‘42248’ has somehow gotten into A1, then in another cell enter: =–TEXT(A1,”d.m”) to retrieve the 1.9 5 [ad_2] solved Regain an original fractional numeric value that Excel has transformed to a date value
[ad_1] BigInteger has the divideAndRemainder(…) method, one that returns a BigInteger array, the first item the division result, and the second, the remainder (which is what mod really does in Java). Update Including comment by Mark Dickinson to other answer: There’s a much simpler linear-time algorithm: set acc to 0, then for each digit d … Read more