The output of from_addr will be there if you are receiving results from your query. Take a look at this example: $string = ‘<hello world>’; echo $string; echo htmlspecialchars(‘<hello world>’); Whereas, echo $string will show in the source code, but is being treated as a tag, and therefore not display “on screen”. Using the htmlspecialchars() … Read more
Use MySQL command with an e option Command mysql -uDBUserName -pUserPassword -DDBName -e=”CALL stored_procedure_name (param1, param2, ….)” Check this 2 solved Call MySQL stored procedure with parameter from batch file
try this you can use an alias for COUNT(*) <?php $connection=mysqli_connect(“host”, “username”, “password”, “database”); $sql=”SELECT COUNT(*) as cnt from database_users”; $res = mysqli_query($connection, $sql); $users = $result->fetch_assoc(); if ($users[‘cnt’] < 4) { ?> // html goes here, outside of the php tags <?php } else { echo “Sorry, you have reached the user account limit.”; … Read more
Please try this: $result = mysqli_query($con,”SELECT * FROM lista”);; ?> <html> <table border=”1″> <?php if (mysqli_num_rows($result) > 0) { // output data of each row while($row = mysqli_fetch_assoc($result)) { ?> <tr> <td><?php echo $row[‘nazwiskoimie’]?></td> </tr> <?php } } ?> </table> </html> 3 solved Mysql and php w/ html database issue
One major reason you have an error in your syntax is that the table is not quoted. Check out the MySQL manual for identifiers (which includes table names). Just like you can’t really use numbers by default to represent variables, you can’t do the same for tables without escaping the identifiers. A couple solutions for … Read more
Solution: Why do you have to compare the passed-on data with the fetched data of your query? It is too redundant, and that loop will slow the process. All you have to do is to use *_num_rows if there is a match. Also consider using _real_escape_string() to sanitize POST data from your form before binding … Read more
Use Join SELECT ocd.category_id, image, parent_id, name FROM oc_category_description AS ocd INNER JOIN oc_category WHERE parent_id = 0 ORDER BY ocd.category_id ASC 2 solved SQL Select Statement joining [duplicate]
Consider the following: <?php $array = array(1,2,3,5,7,11); for($i=1;$i<=12;$i++){ if(in_array($i,$array)){echo $i.’ yes<br>’;} else {echo $i.’ no<br>’;} } ?> Outputs 1 yes 2 yes 3 yes 4 no 5 yes 6 no 7 yes 8 no 9 no 10 no 11 yes 12 no 1 solved How to i fetch all the date in to the select … Read more
In the getRoom.rmview method you fill assign the fields of the rmview instance again and again, but you never modify the roomlist of rmview is never modified; it remains empty. Since you use roomlist in the TableView, there is no data to show. You should instead add a new element for every row the database … Read more
Your solution is going to be a combination of an update and modifying the result using string literals and variables in MySQL. UPDATE <table_name> SET col_name1={expr1|DEFAULT} [, col_name2={expr2|DEFAULT}] … [WHERE where_condition] You are going to need to figure out how to “set” your column to the current value + a string literal. Your question does … Read more
SELECT coll.title AS CollectionTitle, cont.CollectionID, cont.title AS ContainerTitle, cont.ID as ContainerID, cont.LevelContainerID, cont.ContentID, user.Title, user.Value, user.EADElementID FROM tblCollections_Content cont JOIN tblCollections_Collections coll ON cont.collectionid = coll.id JOIN tblCollections_UserFields user ON cont.ContentId = user.ContentId WHERE cont.title is NOT NULL ORDER BY CollectionID, ContainerID I have to assume you have a ContentID column in your tblCollections_Content to … Read more
Just in case you really need it sorted now without redesigning your database (which I would)… $ids = array(1,2,4); $query = “SELECT room_location.*, client_room.*, users.* FROM room_location INNER JOIN client_room ON room_location.user_loc_id = client_room.id INNER JOIN users ON room_location.user_loc_id = users.userGroupLocID WHERE userGroupLocID REGEXP ‘(^|,)(“.implode(‘|’,$ids).”)(,|$)’ ORDER BY room_location.location”; 2 solved Querying comma separated field?
You just have to check the old records for the cleaner on the particular date. Use the following script to get the old records with the date: $prevRecordsQuery= “SELECT COUNT(*) AS records FROM `bookings` WHERE `date` = $date AND `cleaner` = ‘$_post[cleaner]'”; $prevRecords = mysql_query($query); if($prevRecords) echo “This cleaner is fully booked”; else{ $query = … Read more
I’m quite sure this query will work; meaning that it won’t return an error but I’m not certain if it will return correct result as what you intended: SELECT s.Name, SUM(p.Note=5)/COUNT(*) as Anteil FROM Studenten s JOIN pruefen p ON p.MatrNr = s.MatrNr GROUP BY s.Name ORDER BY Anteil DESC, s.Name ASC; If this doesn’t … Read more
Open application\config\autoload.php file and add database into $autoload[‘libraries’] array. Example: $autoload[‘libraries’] = array(‘database’); solved 500 internal server error in codeigniter 3 [closed]