From [-5, 5] to [5, 10]: output = (input + 7.5) * 0.5 From [5, 10] to [-5, 5]: output = (input – 7.5 ) * 2 From [5, 10] to [5, -5]: output = (input – 7.5 ) * -2 The idea is to first shift the average of input’s range to average of … Read more
What you are asking for is a SAT algorithm and it has an exponential complexity, therefore unless you have some extra constraints you must do an exhaustive check (brute force as you said). You may be interested in the function itertools.combinations(iterable, combinations_length) to sum all possible combinations. also you can represent your elements like this: … Read more
Here is an adaptation of your code that doesn’t require storing intermediate results: private Int32 GetHighest(Int32 y, out Int32 totalMax) { var Set = new Int32[] { 4, 3, 2 }; totalMax = int.MinValue; int itemMax = int.MinValue; foreach (var x in Set) { int total = x * (y / x); if(total >= totalMax … Read more
Put the elements of set A into a structure that allows to test set membership in O(1) (for example a hash table or a bit vector if the range of elements is small). This will run in O(n). Now iterate through the set B and check if there is an element in A that is … Read more
As told in the comments, you can see how to check if a number is an integer or not, and perform an appropriate action: Checking if float is an integer. However, if you want more interesting way, without any conditions: float a; float result; cin >> a; result = std::floor(a) – !std::ceil(a – std::floor(a)); // … Read more
You can use the modulo operator to determine whether the word has an even or odd number of letters (% in java) if ( (word.length % 2) == 1 ) { //odd } else { //even } then just split the string in half and compare the reverse of the end with the front int … Read more
Since you tagged this with C++, I would use std::vector objects mixed with the std::sort() algorithm for making it easy to find these stats. Here’s a simple example. #include <algorithm> #include <iostream> #include <vector> int main() { std::vector<float> numbers = { 1, 4, 3, 2 }; std::sort(numbers.begin(), numbers.end()); // numbers = { 1, 2, 3, … Read more
I’ve got what you want, so think in this way: you have original price you want to calculate final transferAmount that: transferAmount = originalPrice + fee but fee here depends on transferAmount fee = transferAmount * 0.029 + 2.25 now solve it: transferAmount = originalPrice + transferAmount * 0.029 + 2.25 transferAmount*(1-0.029) = originalPrice + … Read more
I think this is what you’d like to know: b^x=y x=log(y)/log(b) For b=2 and y=11 you could write something like this: x=log(11)/log(2), where b is the logarithm base, whilst y is the logarithm argument. Therefore, you can calculate any logarithm in a programming language by evaluating it to base 10 first, then dividing it by … Read more
To prove that f(n) = Θ(g(n)), you need to prove that there is a nonzero k such that lim (n → ∞) f(n) / g(n) = k In your case, we want to show that lim (n → ∞) lg(n + a) / (lg n) This is an indeterminate form of type ∞ / ∞, … Read more
Item 1: I’m not versed in k-mer counting and the definition of x is a bit shaky. If you could update your question, then I’ll try to address point 1. But, to me it seems as if you just need to use an algorithm that converts from base 10 back to base 4? Item 2: … Read more
I have solved the problem using the approach proposed by @MBo taking the difference in height and length. Here is the function: public static bool? isLineVertical(Line line) { double xDiff = Math.Abs(line.X2 – line.X1); double yDiff = Math.Abs(line.Y2 – line.Y1); bool? vertical = null; if (yDiff > xDiff) { vertical = true; } else if … Read more
You want to do two things in single shot: Get the integer value if first digit after decimal is 0 Get the rounded value upto last 2 digits if its first digit after decimal is not 0. For second option you can use: newValue = Math.Round(value, 2) Now comes the first requirement: Once you get … Read more
You have several issues here: First of all, your string cu is declared inside the if scope. It will not exist outside that scope. If you need to use it outside the scope of the if, declare it outside. Second, math operations cannot be applied to strings. Why are you casting your numeric values to … Read more
if(choice==1,3,9 && choice2==1,3,9 && choice3==1,3,9){ if( (choice== 1 || 3 || 10) && (choice2== 1 || 3 || 10) && (choice3== 1 || 3 || 10)) //always TRUE if(choice==1,3,11 && choice2==1,3,11 && choice3==1,3,11){ Do you consider these conditions as valid syntax to behave as your needs ? Correct would be if((choice==1 ||choice==3 ||choice==9) && (choice2==1 … Read more