Without getting into a bunch of math, here is a strategy. Identify the face nearest to the camera under some criteria. Two possible criteria for determining the closest face are: a. Finding the closest face based on the Euclidian distance between the face centroid and the camera’s centroid. b. Determine which face normal vector is … Read more
I totally followed this page and used Paint to measure necessary variables # For Blue A = 0.5 B = 2*pi/0.328 C = -0.08 D = 0.5 Blue(x) = 0.5 * sin(2*pi/0.328 * (x – 0.08)) + 0.5 # For Green A = 0.5 B = 2*pi/0.382 C = -0.095 D = 0.5 Green(x) = … Read more
There are no objects here that I can see. You’re using C++ as “a better C”. It’s been a long time since I’ve written C or C++, but I think you want something more like this. I’ve taken the meat out of the main to emphasize my point: #include <iostream> #include <cmath> using namespace std; … Read more
function calculatePrice($numberOfUnits) { // Initialise price $price = 0; // Prices: amount for category => price for category // Starts with largest category $prices = array(150 => 1.5, 100 => 2, 50 => 2.5, 0 => 3); // Loop over price categories foreach($prices as $categoryAmount => $categoryPrice) { // Calculate the numbers that fall into … Read more
The clever authors of the second snippet are rolling their own method of dealing with a very large number such as 50!. Is rather like a multiprecision library and factorial algorithm rolled into one. The first snippet has no such consideration. Even 21! will overflow a signed 64 bit integral type, with undefined results. solved … Read more
Just like you divide this 18 by 2 repeatedly to form a decimal representation for it, you need to do the reverse to convert the decimal part of the number to binary. You need to multiply that decimal portion of the number by 2 repeatedly until it gives a standalone digit. The result(product) of the … Read more
Many notations use “^” as a power operator, but in PHP (and other C-based languages) that is actually the XOR operator. You need to use this ‘pow’ function, there is no power operator. In your code $keone = $vone ^ 2; Should be $keone = pow($vone,2); Rest of your code is fine. That pow function … Read more
As I understand it the function (of two symmetric positive definite matrices) is JL(X,Y) = log( det( (X+Y)/2)) – log( det( X*Y))/2 = log( det( (X+Y)/2)) – (log(det(X)) + log(det(Y)))/2 I reckon the way to do this is to compute the cholesky factorisations of X, Y and (X+Y)/2, that is find lower triangular matrices L,M,N … Read more
Change the increment amount as you please… var arr = []; var i = 1; var incrementAmt = 2000; for(var j = 0; j < 1000; j++) { var num = i + incrementAmt; arr.push(num); i = num; i++; incrementAmt = incrementAmt / 2; // cause incrementer to decrease each iteration } console.log(arr) 1 solved … Read more
Imagine a circle of radius r. It is like a regular polygon with an infinite number of sides. Trigonometry tells us: x = r * cos(a); y = r * sin(a); We know there are 360 degrees or 2pi radians in a circle. So to draw it we would start with angle = 0, calculate … Read more
Modulo arithemtic means that you should use corresponding remainder, not the value itself. In your case: 5 + 25 (mod 26) == 30 % 26 == 4 // <- “%” is taking remainder after dividing on 26 Whatever operation you do in mod 26, the answer will be in 0..25 range. Sample code (C#): int … Read more
The functions execute different mathematical operations: round() rounds a float value to the nearest integer. If either of the two integers on either side are equal distance apart, the even number is picked. Here, the nearest integer is always -6; for -5.5 the nearest even integer is -6, not -5. math.ceil() returns the smallest integer … Read more
The code given looks OK, but if you want the sum without including the last number, as is generally the case you should change the for loop like this for(; index < endno; index ++) solved Sum of the all the numbers between a and b [closed]
Your traceback indicates you are passing a negative number to the math.sqrt() function: >>> from math import sqrt >>> sqrt(4.5 – 5.0) Traceback (most recent call last): File “<stdin>”, line 1, in <module> ValueError: math domain error >>> sqrt(-1.0) Traceback (most recent call last): File “<stdin>”, line 1, in <module> ValueError: math domain error Don’t … Read more
I guess I found the solution. At least, I found the answer I need. Here is my answer import java.math.BigInteger; public class Problem7 { public static void main(String[]args) { int i = 0; int counter = 0; while(true) { if(i>6) { break; } if(i>1) { String str = String.valueOf(i); if (new BigInteger(str).isProbablePrime(i/2)) { System.out.println(str); counter++; … Read more