[ad_1] I think it should be something like this : for(;a<b–;){ for(d += a++ ; a != c ; ) { d += a++; } c+= a&b } The above logic works ! I ran both programs as below and they output the same result : Program1:[derived from your program 1] #include<stdio.h> int main(){ int … Read more
[ad_1] Three loops for each array. Just loop through every array, and append to new array. var size = [‘s’,’m’]; var color = [‘red’,’blue’,’black’]; var material = [‘cotton’,’linen’]; var arrayMaterials = [] for (var i = 0; i < size.length; i++) { for (var j = 0; j < color.length; j++) { for (var k … Read more
[ad_1] jQuery, or javascript in general, can’t really connect directly to a database like you are describing. If you have an endpoint to hit, then jQuery (or vanilla javascript, really) could just fire a request to that endpoint with the specific data: $(‘input:file’).on(‘change’, function(event) { $.ajax({ url: ‘/path/to/endpoint’, type: ‘post’, data: { filename: $(this).val() } … Read more
[ad_1] You mean to do: while iterations < itemsInListOne: listOne[iterations] = float(listOne[iterations]) + 1 Note that you needed to convert it to a float before adding to it. Also note that this could be done more easily with a list comprehension: listOne = [float(x) + 1 for x in listOne] [ad_2] solved How can I … Read more
[ad_1] For loops are iterative statements that repeat a certain block of code , on the other had, if statements are the conditional statements that perform decision making situations. You cannot go from one to other as just as you can’t go from repeating stuff and making decisions in most cases. However, if you wanna … Read more
[ad_1] I don’t understand what the purpose of cin is here, but if you want the output you requested in the question: // Example program #include <iostream> #include <string> using std::cout; using std::endl; int main() { int Day = 20; while (Day >= 1) { cout << Day << ” “; Day /= 2; } … Read more
[ad_1] I want to print a string array containing numbers organized in columns. The array contains {“2″,”1″,”3″,”16″,”8″,”3″,”4″,”1″,”2”} I want to print them in this form 2 16 4 1 8 1 3 3 2 For the the given code of yours, you can do following changes to achieve the result. Find the array length using … Read more
[ad_1] As zipa pointed out, you never break your while loop in the else statement on line 146 unless you run out of tries. A one line “fix” is to simply put an exit() after line 98 within the traverse() function. 3 [ad_2] solved Udacity python code a quiz [closed]
[ad_1] Here you are: #include <stdio.h> #include <string.h> int main( void ) { const char *s = “ABCDEFGHIJKLMNOPQRSTUVWXYZ”; const size_t N = strlen(s); while (1) { printf(“Enter a non-negative number (0 – exit): “); size_t n; if (scanf(“%zu”, &n) != 1 || n == 0) break; size_t k = 0; for (size_t i = 0; … Read more
[ad_1] You are not reconstructing an array in your foreach loop. So your $od variable does just get overridden each time you loop. Your code should be foreach($_POST[‘gm’] as $key => $answer) { if($answer != ”) { $odd = explode(” “,$answer); $od[] = trim($odd[0]); } } $total = array_product($od); echo $total; 0 [ad_2] solved How … Read more
[ad_1] I’m assuming this is homework or something and you are supposed to do this a certain way or something? What are the specifications? I shortened your code anyway if that helps in any way p = “Sorting1234” upper_case = sorted([i for i in p if i.isupper()]) lower_case = sorted([i for i in p if … Read more
[ad_1] I would do something like this: char const* sep = “”; // item separator (nothing to begin with) for(a;a<=b;a++) { if(a%3 == 0 && a%2 != 0) { cout << sep << a; // output the separator before the next value sep = “, “; // now change it to a comma } } … Read more
[ad_1] Here is a way you could achieve your purpose. int num = 2; // for example int out = 1; for (int exp = 1; exp <= 10; exp++) { out *= num; printf(“%d\n”, out); } Remarks about your code: Your inner while loop is infinite if num and expnt are both different from … Read more
[ad_1] If you set j = i then the minimum distance would be zero since you’d be computing the distance between a point with itself! If you set j = 0 the above would still apply, albeit with unnecessary duplicated comprisons, since you’d be including j == i. [ad_2] solved what happens when we change … Read more
[ad_1] #include <stdio.h> int seq(void){ static int v = 5, d = 1; int ret = v; v += d; if(v == 5 || v == 7) d = -d; return ret; } int main(void) { for(int i = 0; i < 20; ++i) printf(“%d “, seq()); return 0; } 1 [ad_2] solved How to … Read more