Not sure what you mean with “store the data of ‘li1’ into an index”. I’m assuming you want a list of lists? You could append the list. k = “/BTC” result_list = [] for i in range(l): if k in dat1[“Data”][i][‘Label’]: value = dat1[“Data”][i][‘Label’] value1 = dat1[“Data”][i][‘TradePairId’] value2 = dat1[“Data”][i][‘AskPrice’] value3 = dat1[“Data”][i][‘BidPrice’] result_list.append([value, value1, … Read more
Literally write it as you would say it! >>> [‘a’ if i % 2 else ‘b’ for i in range(10)] [‘b’, ‘a’, ‘b’, ‘a’, ‘b’, ‘a’, ‘b’, ‘a’, ‘b’, ‘a’] 2 solved Creating a list that gives a specific value at even indexes and another value at odd indexes
You can try using list comprehensions with a combination of joining and splitting: your_list = [[int(j) for j in i.split()] for i in ‘ ‘.join(data).split(‘<>’)] 6 solved breaking a list in to lists in python?
You need to split each string into each port, then print each one. And you can use enumerate() to get the line number. # Example data port_strings = [ ‘443, 9993’, ‘443, 3389, 445’, ‘443, 22, 3389, 23’, ‘3389, 445, 443’, ‘443, 3389, 445’] for i, port_string in enumerate(port_strings, 1): print(‘line’, i) for port in … Read more
I may have been massively over complicating things here, this appears to do what I want (ignoring the insertion of completely new markets / selection_id’s for now): new_order_list = [] for x in updated_orders: for y in x[‘Live_orders’]: orders_to_update = {} orders_to_update.update({‘Market_id’: x[‘Market_id’], ‘Selection_id’: y[‘selection_id’], ‘live_orders’: y[‘live_orders’]}) new_order_list.append(orders_to_update) for z in new_order_list: for a in … Read more
str(tuple(str(fv[“v”]).split(‘,’))) will probably give you what you want but if you give more information there is definitely a better way to write this. What does fv[‘v’] consist of? 2 solved TypeError: cannot concatenate ‘str’ and ‘list’ objects. how to convert list to string [closed]
ord() function will return the ascii value of a character. The 2nd point says that you create a list of length 26 (as english letters are 26) and each entry will have the frequency of that letter. Eg: ‘a’ = 0; ‘b’ = 1;… ‘z’: 25 ord(‘a’) gives 97 – ASCII value of ‘a’. Create … Read more
You need a way to associate the inventory level of the ingredients (which you have as your double variables), with the order id of the ingredient (which is the result you want at the end). One solution would be to use an Ingredient class that might look something like this: public class Ingredient { public … Read more
def identify_cycles(l1, l2): d1 = {val: idx for idx, val in enumerate(l1)} # This assumes unique values in input l1, but I think the question does too out = [] for idx, val in enumerate(l1): curr = l2[idx] if curr == val or any(val in s for s in out): continue # If this value … Read more
>>> l = [1,2,3,4,5,6] >>> N = len(l) >>> revL = l[::-1] >>> revL [6, 5, 4, 3, 2, 1] >>> for i in range(1,N): … print revL[-i:] + revL[:(N-i)] … [1, 6, 5, 4, 3, 2] [2, 1, 6, 5, 4, 3] [3, 2, 1, 6, 5, 4] [4, 3, 2, 1, 6, 5] … Read more
It could be as simple as from csv import reader from random import choice with open(myfile, newline=””) as in_f: rd = csv.reader(in_f) choices = [choice(row) for row in rd] (no need to make individual lists) 2 solved Write each individual row of a csv as a separate list (python)
You may want to look into python’s list comprehension. arr = [int(arr_temp) for arr_temp in input().strip().split(‘ ‘)] Let me answer this with an example, suppose you input : 1 3 4 29 12 -2 0 the input function reads this as a string The strip function eliminates whitespace from both ends of the string, The … Read more
to add another options to all these good answers, another one with lambda: l = [4,3,3,2,1,0,1,2] f= lambda x,i : 0 if 0 in x[:i] else x[i] [f(l,i) for i in range(len(l))] output: [4, 3, 3, 2, 1, 0, 0, 0] 1 solved List elements to equal zero after 0 element
You can use the map and abs functions to accomplish this: In [1]: sorted(map(abs, lista)) Out[1]: [1, 2, 3, 5, 7, 8] To do this with the code you wrote, you can # The list defined above lista = [a,b,c,d] # Sorted from least to greatest absolute value sorted_abs_list = sorted(map(abs, lista)) # Sorted from … Read more
You have your counter incrementing in the wrong place. int count = 0; foreach (string[] element in logBook) { Console.WriteLine (“#{0}: {1}”, count, element[0]); count++; // Increment after you print } solved C# How to start list count on 0 [closed]