Its clear in Official Docs jQuery.getJSON() $.ajax({ dataType: “json”, url: “http://confidential.com/pcm/datamobile.asmx/ObtenerContactos”, data: {sessionId: 1}, success: function(data) { alert(“Success!!! yay”); peopleList = data; jsonIsLoaded();//output your data to console } }); 1 solved What would be the $.ajax equivalent to this $.getJSON
Just map them per index (if they have the same length) in a simple loop. Here is a demo: a = [“Isolated-1”, “SVT_FedPortGroup”, “SVT_StoragePortGroup”, “VM Network”, “test-pg-2002”] b = [“target_Isolated-1”, “target_SVT_FedPortGroup”, “target_SVT_StoragePortGroup”, “target_VM Network”, “target_test-pg-2002”] c = { “NetworkMaps”: [] } for (var i = 0; i < a.length; i++) { c.NetworkMaps.push({ “ENVID”: null, “SourcePG”: … Read more
This is basically a json stirng. Check more about it here: JSON (JavaScript Object Notation) is a lightweight data-interchange format. It is easy for humans to read and write. It is easy for machines to parse and generate. It is based on a subset of the JavaScript Programming Language, Standard ECMA-262 3rd Edition – December … Read more
use foreach foreach($arr as $element){ echo $element[0]; echo $element[1]; } 1 solved how i can browse a JSON object
try like this,you can get the value like below NSString* firstName = [[jsondata objectForKey:@”author”]objectForKey:@”firstName”]; 5 solved How to retrive JSON objects in a NSString [closed]
after converting: for k, v in obj[0].items(): print k, j this will print: c -4.88 ccol chr e NASDAQ ltt 10:23AM EST cp_fix -0.67 c_fix -4.88 l 720.01 s 0 lt Nov 10, 10:23AM EST pcls_fix 724.89 t GOOG lt_dts 2015-11-10T10:23:21Z l_fix 720.01 cp -0.67 id 304466804484872 l_cur 720.01 see no ‘u’ there solved How … Read more
Your “JSON string” seems to be JavaScript code that you would have in a script tag that creates a drivers JavaScript object with a property called driver that is an array of other objects. To be JSON, you remove the var drivers = and the semicolon at the end leaving just what you would set … Read more
var data = … the initial array var result = {}; for (var i = 0; i < data.length; i++) { var element = data[i]; result[element.id] = element; }; 3 solved Coverting json array to js objects
After looking at the data, it looks like their are two problems. Your collection of orders and items are not closed. The main json object is not closed. Let’s start with the Order and Item collection: The item collection in the order with recordId 3 is not closed properly. This is resulting in the order … Read more
Introduction If you are working with JSON data and you encounter the error “Expecting ‘STRING’, got ‘}’”, you may be wondering how to fix it. This error occurs when the JSON data is not properly formatted. In this article, we will discuss the causes of this error and how to fix it. We will also … Read more
Try using Codable to parse the JSON response. Create the models like, struct Root: Decodable { let data: Response } struct Response: Decodable { let timeIn: String let timeOut: String } Now parse your JSON data like, if let data = data { do { let decoder = JSONDecoder() decoder.keyDecodingStrategy = .convertFromSnakeCase let response = … Read more
You can encode an array thus: $cars = [ ‘ALFA’ => [ ‘title’ => ‘Alfa Romeo’, ‘models’ => [ … ] ], ‘ACURA’ => [ ‘title’ => ‘Acura’, ‘models’ => [ … ] ], ]; This can then be run through json_encode(). solved Generating JSON with PHP [closed]
If you just need to remove ” from a string you can use the str_replace method. $new_str = str_replace(“\””, “”, json); I hope I was helpful. 4 solved How to remove double quotes from json {“x”:”y”} to {x:y} in php [closed]
Thanks for the advices guys. But I found the way on how to do it. I only changed the pickQuestion function. func pickQuestion () { if Questions.count > 0 && questionscount < 8{ QNumber = Int(arc4random_uniform(UInt32(Questions.filter{$0.Question.hasPrefix(“KEK”)}.count))) questionscount += 1 questionLabel.text = Questions.filter{$0.Question.hasPrefix(“KEK”)}[QNumber].Question self.title = “Ερώτηση: \(Int(questionscount))/50” answerNumber = Questions[QNumber].Answer for i in 0..<buttons.count{ buttons[i].setTitle(Questions[QNumber].Answers[i], for: … Read more
You can try like this, and your root is Json array not jsonobject try { JSONArray jsonArray = new JSONArray(d); if(jsonArray != null) { for (int i = 0; i < jsonArray.length(); i++) { JSONObject jsonObject = jsonArray.optJSONObject(i); if(jsonObject == null) { continue; } String name = jsonObject.optString(“name”); String isMe = jsonObject.optString(“isMe”); String time = … Read more