If I am reading your question right, the result table give you the age ID and Period, and then the count of toys per age ID and Period. Here is how you would write that query: SELECT Ages.ID, Ages.Period, IFNULL(sub.cnt,0) AS Count FROM Ages LEFT JOIN (SELECT Toys.age_id, COUNT(*) AS cnt FROM Toys GROUP BY … Read more
You can use LEFT JOIN and then get SUM of the AMOUNT by grouping rows with the same CUST_ID : SELECT t2.CUST_ID , COALESCE(SUM(t1.AMOUNT), 0) AS TOTAL FROM cus t2 LEFT JOIN pur t1 ON t1.CUST_ID = t2.CUST_ID GROUP BY t2.CUST_ID ORDER BY TOTAL SQLFiddle 2 solved join two columns with same title but in … Read more
With 2 courses you are always going to get 2 rows when joining like this. It will give you the minimum date value for each course. The first way you can get a single row is to use TOP 1 in your query, which will simply give you the course with the earliest test date. … Read more
Let’s take it step-by-step… First, the entities you’re selecting are in the leave_request table. So let’s start there: SELECT leave_request.* FROM leave_request Now, you need to know the data for the applied_by column in the desired results. So you join the staff table: SELECT applied_staff.name AS applied_by FROM leave_request INNER JOIN staff AS applied_staff ON … Read more
If you just want the max score per student you can aggregate the rows before joining: select s.id_student, u.name, u.role, s.status, u.no_phone, s.exam_status, sc.score from student s join user u on u.username = s.id_student join ( select Max(score) as score, id_student from score group id_student )sc on sc.id_student = s.id_student where mod(s.id_student, 2) = 0 … Read more
Using max(ship_num) is a good idea, but you should use the analytic version (with an OVER clause). select * from ( select t.*, max(ship_num) over (partition by order_id) as orders_max_ship_num from table1 t1 ) with_max where ship_num = orders_max_ship_num order by order_id, item_code; 0 solved Joins and/or Sub queries or Ranking functions
I’m sure you can work this out yourself.. I guess it needs to look something like this.. but you don’t say how you want the data to be combined so I’ve just just a cross product (the WHERE 1=1) of the last data set to a union of the first two with PH AS( SELECT … Read more
split is not working on empty separators. Just use the string: print(“-“.join(string)) solved What is wrong in this code here
A left outer join assuming the first table is used first. A SQL syntax for the above would be: SELECT * FROM Table1 LEFT JOIN Table2 On Table1.ID1=Table2.ID2 solved Joining two tables without filtering the data on the basis of joining condition
Without a better understanding of the rules and data this is the best I can come up with. It is based on your first array example – SELECT `r`.* FROM `rule_attribute_value` `rav` INNER JOIN `rule` `r` ON `rav`.`rule_id` = `r`.`rule_id` INNER JOIN `rule_attribute` `ra` ON `rav`.`attribute_id` = `ra`.`attribute_id` WHERE (`rav`.`store_id` = 0 AND `ra`.`attribute_code` = … Read more
SELECT * FROM section_user_map JOIN users USING (UID) JOIN verification USING (UID) WHERE SectionID = 65 AND CompleteDate BETWEEN ‘2012-05-09 12:00:00’ AND ‘2012-05-11 12:00:00’ See it on sqlfiddle. No UNION required. Outer join would only be required if you still want to return results for users who do not exist in one (or both) of … Read more
UPDATE b SET b.c1 = b.c2 – b.c3 FROM a JOIN b ON … JOIN c ON … solved SQL Join with subquery
A simple merge using df.merge does this: df1.merge(df2, on=[‘A’]) A B_x B_y 0 a 1 3 1 a 1 4 2 a 2 3 3 a 2 4 4 b 1 3 5 b 2 3 2 solved Merging two dataframes in python pandas [duplicate]
Please put your queries in text, not images. You can use JOINS to achieve this or you can do like this SELECT A.ID, A.DATE,A.AMOUNT, B.NAME FROM test_T_cust A INNER JOIN test_M_cust B ON A.ID=B.ID AND A.DATE BETWEEN B.V_FROM AND B.V_TO; 3 solved How to join tables in SQL Server by date Valid_from/Valid_to
There are a few small mistakes in your query. In the ‘From’ section you only need to use the first table, and you’ll need to tell the join which field from the first table matches which field in the second table. In the where you’ll only have to match one field to $savingsId This query … Read more