keyup() is your answer: $(‘#word’).keyup(function(e) { if(e.which == 13) { // Do your stuff } }); e.which returns the scan/character code of the pressed key. 13 is for ENTER. You can find other codes here. 1 solved Running a function when enter is pressed in a text box [closed]
You don’t have pageTypeId property in the object. Because of that, i changed this property to id in the statement, and if you want filter value 1 or 2, i used || characters. Maybe you will edit your code like this, it will work. let tmpArray = [{“id”:”1″},{“id”:”2″},{“id”:”2″},{“id”:”3″},{“id”:”3″}]; this.nodes = tmpArray.filter(x => { return x.id.toString() … Read more
It depends on what myObj is and where myObj.$().trigger(“name”) is found. In the past, I’ve seen similar methods where an object (say a view or controller within an MV* framework) has a $() method associated with it. The call to $() might return a jQuery wrapped element associated with the view (either constructed by the … Read more
You can use String#match with a RegExp. You can use Array#map afterwards to convert the strings to numbers if needed. var str=”156p1m2s33c”; var numbers = str.match(/\d+/g); console.log(numbers); What’s wrong in your code: cust_code and url are not part of the function. Refer to str. You declare prodId twice. You don’t handle the number between “s” … Read more
Using jQuery the code will become function openNav() { $(“#myNav”).height(“100%”); } function closeNav() { $(“myNav”).height(“0%”); } solved how to translate plain javascript in jquery
First thing you dont need to apologie for been a newbie , we all were newbie at some point in our career and we still learn new thing everyday Second you need to use filter on the second array and return a new array based on the index that you did filterd var array1 = … Read more
This is a math problem, but computers help to solve it using linear forumla (as suggested by @cmgchess in comments): var x1 = 10; var x2 = 100; var y1 = 2; var y2 = 15; var x_inp = 6; // var y_out = ? ? ? var calcY = getLinearFunction(x1, y1, x2, y2); console.log(calcY(6)) … Read more
If you were going to augment a built-in prototype to do this, it would make more sense to augment Element.prototype, not String.prototype, since what you’re trying to use hide on isn’t a string, it’s an HTMLElement instance (which inherits from Element). But it’s usually not a good idea to augment/extend the built-in prototypes. It’s fragile. … Read more
var array1 = [“column1”, “column2”, “column3”] var array2 = [“infor1”, “infor2”, “infor3”] var obj = {}; array1.forEach(function(y, z) { obj[y] = array2[z]; }); console.log(obj) 0 solved How to set array to object keys javascript [duplicate]
Method 1: $(‘[id^=”del”]’).click(function() { //ID begins with “del” //code here }); //or $(document).on(‘click’, ‘[id^=”del”]’, function(e) { //code here }); Method 2: Add a common class to all your buttons: $(‘.myButton’).click(function(){/*code..*/}); solved jQuery: onclick method for every buttons with id starting with [duplicate]
let list = [{ advance_amount: “100”, id: “SUBMH9876”, created_by: “12346”, created_date: “Thu, 08 Nov 2018 11:23:00 GMT” }, { advance_amount: “200”, id: “SUBIH9876”, created_by: “12346”, created_date: “Thu, 08 Nov 2018 11:23:00 GMT” } ]; var subArr = list.map((item) => { return { id: item.id } }); console.log(subArr) solved How to push particular key from array … Read more
If I understand correctly something like this should work: Object.entries(testData).forEach(function (entry) { if (actualObject[entry[0]] === entry[1].trim()) { //answers match } else { //answers don’t match } }); If you need to compare regardless of case then change entry[1].trim() to entry[1].trim().toLowerCase(). EDIT: Just to remind you that maybe you should add a check whether or not … Read more
Use filter instead of find: The filter() method creates a new array with all elements that pass the test. While The find() method returns the value of the first element searchEnseigne(){ let server = this.products.filter(x => x.enseigne === “McDonalds”); console.log(server); } 0 solved How can i display more than one array elements that satisfy a … Read more
using reduce makes it fairly simple const timings = [{ monday: { from: “12:00”, to: “13:00” }, tuesday: { from: “11:00”, to: “13:00” }, thursday: { from: “11:00”, to: “13:00” }, friday: { from: “11:00”, to: “13:00” }, saturday: { from: “11:00”, to: “13:00” }, }, { monday: { from: “10:00”, to: “17:00” }, tuesday: … Read more
Use array find: var languages = [ {“name”: “english”, “iso_639_2_code”: “eng”}, {“name”: “esperanto”,”iso_639_2_code”: “epo”}, {“name”: “estonian”,”iso_639_2_code”: “est”} ]; var user = [{name: “john”,language: “eng”,country: “US”}]; var language = languages.find(l => l.iso_639_2_code === user[0].language); var languageName = language && language.name; // <– also prevent error when there is no corresponding language found console.log(languageName); EDIT: With multiple … Read more