In the Long class, there is a handy static function numberOfTrailingZeros, which does almost what you want, except that it returns zero (instead of -1) when the input is not divisible by 2. You could handle that case in different ways. For example, extending the answer of @0x476f72616e if ((num & 0x1) == 0) return … Read more
Here is an example of what you are trying to do. import java.util.ArrayList; import java.util.Arrays; public class Test{ public static void main(String[] args) { ArrayList<Integer> numberList = Arrays.asList(10234, 20233, 34546, 43546, 59865, 70002, 92435, 200354); for(int nbr : numberList){ //goes through the list if( nbr > 20000 && nbr < 50000){ System.out.println(nbr); } } } … Read more
There are two possbile solutions. The first one is to override the equals method. Simply add: public class DataRecord { […..] private String TUN; @Override public boolean equals(Object o) { if (o instanceof DataRecord) { DataRecord that = (DataRecord) o; return Objects.equals(this.TUN, that.TUN); } return false; } @Override public int hashCode() { return Objects.hashCode(TUN); } … Read more
first you have typo instead of Int it should be int. Answer :- if we want specify dimension before the variable, that facility is applicable only for first variable in a declaration. If we are trying to apply for remaining variables, we will get compile time error. 1. a=1, b=1; 2. a=2, b=1; 3. a=2, … Read more
First split the string. Then parse each element in String array to new array String[] s=str.split(“\\D+”); int[] intarray=new int[s.length]; for(int i=0;i<s.length;i++){ intarray[i]=Integer.parseInt(s[i]); } solved How to extract numbers from a String into an array
You need to replace the charAt method with the substring method: String vacantion = “Vacantion”; int number = 1; for (int i = 0; i < vacantion.length(); i++) { System.out.println(vacantion.substring(vacantion.length() – number)); number++; } 0 solved How do I get the last character, then last two so on.. of a string?
Well, you could try: Example 1: Using REGEX public static void main(String[] args) { String text = “Hello worlld this is someething cool!”; //add # between all double letters String processingOfText = text.replaceAll(“(\\w)\\1”, “$1#$1”); System.out.println(processingOfText); } Example 2: Using string manipulations public static void main(String[] args) { String text = “Hello worlld this is someething … Read more
This should work 🙂 String num1 = mEtfirst.getText().toString(); char[] temp = num1.toCharArray(); int i=0; num1=””; while(Character.isDigit(temp[i])) num1=num1+Character.toString(temp[i++]); This converts the string to a character array, checks the array character by character, and stores it in num1 until a non-digit character is encountered. Edit: Also, if you want to convert num1 to an integer, use: num1=Integer.parseInt(num1); … Read more
As the error says, an abstract class cannot be instantiated, i.e., we cannot precede it with the word new, unless you also add the class body and implement any abstract methods. Alternately, you can create a class that extends Handler, and again make sure to add all of the abstract methods. new Handler() { @Override … Read more
There is an r missing public void actionPerfomed(ActionEvent e) ^^^ public void actionPerformed(ActionEvent e) solved Method is not abstract and does not override method in Interface error
If I can guess what you might be doing, I came up with this and it is working. Please have a look: import java.math.BigDecimal; import java.util.*; public class MyTest { public static void main(String[] args) { BigDecimal myBigDecimal = new BigDecimal(11); Map<Integer, String> myMap = new HashMap<Integer, String>(); myMap.put(new Integer(11), “Hello World!”); String message = … Read more
It means that the string is initialized as an empty string firstly. To use a variable, we should give it an initial value and this is called initializing the variable. Otherwise the compiler will throw an error. solved What does it mean when i write String line = “” [closed]
You can use the .indexOf(Object o) method which returns, as the java 8 documentation specifies: the index of the first occurrence of the specified element in this list, or -1 if this list does not contain the element You can also use .lastIndexOf(Object o) which, as you would guess, will return the last occurrence of … Read more
You should write script in another file and add ng-app Here is plnkr https://plnkr.co/edit/yvJGX52osH9eTJggexec?p=preview your problem is you include file script above angular.js . include below and problem will solved <link rel=”stylesheet” href=”https://stackoverflow.com/questions/43739301/script/bootstrap.css”> <script> type=”text/javascript” src=”script/angular.js”></script> <script> type=”text/javascript” src=”script/angular.min.js”></script> <script> type=”text/javascript” src=”script/bootstrap.js”></script> <script type=”text/javascript” src=”script/bootstrap.min.js”></script> <link rel=”stylesheet” href=”css/app.css”> <script src=”script/tuto.js”></script> //include below 2 solved ngRepeat … Read more
Curl is used for sending HTTP requests. Maybe you want to issue the rm command via ssh? From this stackexchange question: ssh hostname “rm /myfolder/myFile.zip” 1 solved Delete file in linux server using curl command