I didn’t test this out but it should look something like this… public void DoGet(HttpRequest request, HttpResponse response) { var content = request.Params[“content”]; response.ContentType = “text/calendar”; response.AddHeader(“Content-length”, content.Length.ToString()); response.AddHeader(“Content-disposition”, “attachment; filename=event.ics”); response.Write(content); } solved ASP.NET equivalent of the java code [closed]
I actually think of them as “constants” (static final does not directly imply a constant for any Type in Java), say i have a enum like this: public enum ModeEnum { FAIL_FAST, FAIL_RETRY, HUNDRET_MORE_MODES } And a Interface like this: public interface ISample { static final ModeEnum DEFAULT_MODE = ModeEnum.FAIL_FAST; public void process(ModeEnum mode); } … Read more
Use an array of pokemon In main() pokemon[] trainer = new pokemon[6]; trainer[0] = new pokemon(); trainer[0].name = “pikachu”; //… //trainer[1] .. Till 5 And opponent could be class opponent{ String name; pokemon[] pokes; } You can set them similarily as trainer Edit: As I have my own pokemon game, just wanted to clear you … Read more
private void setCommission() { commission = (artists * 40); } solved How do I create a method to calculate a commission fee in Java
Try this: String category = “1-4-5-10-13-27-28-29-32-34-35-36-51-58-150”; String [] categoryArray = category.split(“-“); Then if you want to end up with an ArrayList<String> do: List<String> categoryArrayList = new ArrayList<String>(); Collections.addAll(categoryArrayList, categoryArray); solved converting String to string array
Here’s what you’re looking for: while ((sourceLine = source.readLine()) != null) { arrayList.add(sourceLine); } 2 solved Java get List from a Website [closed]
One of the problems is with this line: if (pass1 == newname & pass2 == newpassword){ System.out.println(“you are logged in”); }else{ System.out.println(“incorrect passoword or login”); } If you will debug this code, You will notice that this if statement, doesn’t compare the values of the String. For more details you may visit: https://stackoverflow.com/questions/513832/how-do-i-compare-strings-in-java Try this … Read more
java.io.DataInputStream.readFloat() which invokes java.lang.Float.intBitsToFloat(int bits), you may try it. (read the api doc first) solved breaking float value in char and transmit it on tcp and read using java program [closed]
Perhaps this is what you are looking for import java.util.Scanner; class A{ public static int []PriorGreen = new int[6]; public static int []AfterGreen = new int[6]; public static String []month = {“Jan”,”Feb”,”Mar”,”April”,”May”,”June”}; static void PriorG() { System.out.println(” Enter Cost for Prior Green Month’s Below !!!”); Scanner in = new Scanner(System.in); for(int i=0;i<6;i++){ System.out.println(” Please enter … Read more
remove below code from toString() Scanner in = new Scanner(System.in); System.out.print(“Enter a name: “); name = in.next(); System.out.print(“Enter a meal: “); mealType = in.next(); You are already reading these from the for loop. Also, your do-while loop is all wrong. The condition doesn’t make sense. It should be option > 0 && option <4 3 … Read more
Thanks for all answers by you. I got my answer for my question as i was trying.. sorry for uploading it late but got so many other ways to do it. Here is my answer. String res = “”; public String altPairs(String str) { int i=0; while (i<str.length()) { res +=str.charAt(i); i=i+1; if(i<str.length()) { res+=str.charAt(i); … Read more
findViewById takes an int argument not a string: findViewById(R.id.bAdd); 5 solved android application stopped working not showing demo on emulator
It’s easy: Read you first file line by line (you can use a Scanner for that). For each line, write it to the output file (you can use a PrintWriter for that). Also store the line in a HashSet. Read your second file line by line. For each line, check if the line is in … Read more
What is this concept called in JAVA? This is not a concept , you have named the method same in two un-related classes . If one of the class was sub class of another then depending on the method signature , it would have been overriding or overloading. You would have implemented run time polymorphism … Read more
if (t <0 && t>11) System.exit(0); A number can’t be smaller than 0 and bigger than 11 at the same point in time. Or to be precise: the numerical types that Java support don’t allow for that. In that sense, you probably meant: if (numberFromUser < 0 || numberFromUser > 11) { System.out.println(“number ” + … Read more