[Solved] Java program. How do I loop my “isLucky” method through my array? Also, how do I print my results correctly in the main method?

Your compiler error, ‘else’ without ‘if’ is because you have something like this: if(isOkay) doSomething(); andThenDoSomethingElse(); else doAnotherThing(); andEvenSomethingElse(); And you must put each block in curly braces, like this: if(isOkay) { doSomething(); andThenDoSomethingElse(); } else { doAnotherThing(); andEvenSomethingElse(); } I strongly recommend using curly braces in all ifs (and whiles and fors and everything … Read more

[Solved] How to handle JTextField value retainment without add it into a Dialog? [closed]

To solve the problem declare the textfield as static: //JTextField Declaration and Initialization static JTextField NODES_TEXT_FIELD = new JTextField(); After that catch the value of the TextField: int nodes = Integer.valueOf(NODES_TEXT_FIELD.getText()); In my case was an int value, switch yourself; After that clear the value of the textfield cos it will be stored since the … Read more

[Solved] I can’t access Genre class

As JohnnyMopp mentioned above, you don’t add any genre into list. Change your code like following: public Catalogue() { this.genres = new LinkedList<Genre>(); Genre programming = new Genre(“Programming”); Genre drama = new Genre(“Drama”); this.genres.add(programming); this.genres.add(drama); booksAvailable.add(new Book(“Swift”, 1999, programming, 20)); booksAvailable.add(new Book(“TheAlChemist”, 2000, drama, 20)); //Name of a book, year of publication, genre, price } … Read more

[Solved] Stringoutofboundexception for string

i know scan.nextline() gives a character No, it gives a string. So is there anyway to handle an exception in such a way that i am able to manage to keep string after scan.nextline(). The real problem is that you are not handling the case where nextLine() returns an empty string. You cannot retrieve characters … Read more

[Solved] Java realtime writing file when it’s opened

Interesting: Lets deal this in simple way. 1. Save a file test.txt somewhere. 2. Open that file and keep it opened In Java write to this file (Standard Code) FileWriter fw = new FileWriter(new FileOutputStream(new File(“c:/test.txt”))); fw.write(“ABC”) Now go to notepad file again. I normally used Textpad it does refresh automatically (by an alert) because … Read more

[Solved] Null result for date object fetched from DB giving sysDate/current date on mapping to Java object

Found the reason. When the BeanPropertyRowMapper was provided with Date.class for mapping, new Date() is called for instantiation of the class like for any object. But for Date.class, new Date() returns sysDate. solved Null result for date object fetched from DB giving sysDate/current date on mapping to Java object

[Solved] Passing data and add other data to it and pass it again [duplicate]

Activity A: pass data to activity B Intent i = new Intent(getApplicationContext,ActivityB.class); i.putExtra(“DataA”,dataA); i.startActivity(i); retrive data in ActvityB String a; Intent i = getIntent(); a= i.getStringExtra(“DataA”); pass data in actvityc from ActivityB Intent i = new Intent(getApplicationContext,ActivityC.class); i.putExtra(“DataA”,a); i.putExtra(“DataB”,b); i.startActivity(i); retrive data in ActvityC String a,b; Intent i = getIntent(); a= i.getStringExtra(“DataA”); b= i.getStringExtra(“DataB”); solved … Read more

[Solved] How can we split the word into characters in android/java..?? and assign particular id to each character [closed]

I assume that you have maintained a map for mapping your characters with some numbers. Then you can simply split your string on empty string to get individual characters. And then iterate over your array to get the sum. Note, that, splitting on empty string will get you an empty string as first element in … Read more

[Solved] How to convert java Map to delimited format [closed]

You can use a class like this one: import java.util.*; class LegacyGlueifier { private LegacyGlueifier() { } public static String generateLegacyDataset(Map<String, String> data) { final ArrayList<ArrayList<String>> lists = new ArrayList<ArrayList<String>>(); final int width = data.size(); int i = 0; for (Map.Entry<String, String> entry : data.entrySet()) { String[] values = entry.getValue().split(“,”); changeDims(lists, width, values.length + 1); … Read more

[Solved] How to get every String from an ArrayList [closed]

Use this code for your problem: in the other method public String convertToString(ArrayList<String> al) { String str =”” ; for(int i=0; i<al.size;i++){str+=al.get(i)+” “;} return str; } If i understand your query correctly then this is the solution 0 solved How to get every String from an ArrayList [closed]