You are confusing artifacts of the Java programming language with items of the constant pool of a class file holding Java byte code. Class literals of the form type.class, as well as an access to the length of an array of the form array.length may look like a member access in the source code but … Read more
Your id textview1 is doubled, it is set to the linear layout and to the textview Change one of them 0 solved java.lang.ClassCastException: android.widget.LinearLayout cannot be cast to android.widget.TextView populateview
Don’t use square brackets with your ArrayList. Lists are not arrays. ArrayList<Integer> list = new ArrayList<>(5); Add to it with list.add(sc.nextInt()); Remove from it with list.remove(index); 2 solved I can’t understand ArrayList[]= new Arraylist[]; declaration.
The trivial answer is to split the string: String[] fragments = theString.split(” “, 6); Given that the fragments have specific meanings (and presumably you want some of them as non-string types), it might be more readable to use a Scanner: Scanner sc = new Scanner(theString); int x = sc.nextInt(); int y = sc.nextInt(); int width … Read more
String.valueOf().length() returns 11 because that is the number of digits/characters in the output (i.e. [@936016386 – an address – has 11 characters) solved How do I properly test the char[ ] fields in my custom object for nulls, blanks, or empty? and Why do char[ ] indicate a length of 11?
simple answer: NO. here is a nice article that points out .. how the definition for a “real” OO language.. can not be done. There are different relationships between object orientation and computer languages: support of OO, ubiquitous use of OO, and enforcement of OO. Again, I’d recommend some effort to be unambiguous: e.g. “Java … Read more
This can be used to loop over the array and print “yes ” or “no ” : boolean[] newbirds = {false, true, true}; StringBuilder sb = new StringBuilder(); for(boolean bird : newbirds){ sb.append(bird? “yes ” : “no “); } System.out.println(sb.toString()); solved java -change boolean to yes no
You can try with array.stream().map(s->”\””+s+”\””).collect(Collectors.joining(“, “)); which will first surround each strings with quotes, then join them using , For Java 7 String delimiter = “, “; StringBuilder sb = new StringBuilder(); if (!array.isEmpty()) { sb.append(‘”‘).append(array.get(0)).append(‘”‘); } for (int i = 1; i < array.size(); i++) { sb.append(delimiter).append(‘”‘).append(array.get(i)).append(‘”‘); } String result = sb.toString(); 3 solved … Read more
Try the intersectsLine(Line2D l) method of java.awt.geom.Rectangle2D: Rectangle2D.Double rect = new Rectangle2D.Double(double x, double y, double w, double h); System.out.println(rect.intersectsLine(new Line2D.Double(double xA, double yA, double xB, double yB))); where xA,yA, xB,yB are the x and y coordinates, respectively, of points A and B which you wish to check if the rectangle is between. solved Check … Read more
Not sure what trouble you’re having. I wrote: public class Quad { public static void main(String[] args) { double a = Double.parseDouble(args[0]); double b = Double.parseDouble(args[1]); System.out.println(Math.abs(b/a – 200.0)); if (Math.abs(b/a – 200.0) < 1.0e-4) { System.out.println(“first one”); } else { System.out.println(“second one”); } } } And some output: animato:~/src/Java/SO$ java Quad 1 200 0.0 … Read more
You have a typo: SELECT * FROM studentdetail instead of SELECT * FORM studentdetail solved select * in java error
-1 is returned when you don’t find the value. The loop says for each character (here called value) inside chArray try to locate another identical character in targetStr, if you don’t find another add the character to targetStr. So basically if you enter hello it would go like this: value = h -> try to … Read more
Okay, after so much discussion and so many issues with your code I have totally revised your original code because you said you wanted to learn more. Among other improvements I have done the following changes: Meaninfgul class name Meaningful method and parameter names Convert repeated and often used constants like 50 and the array … Read more
After you click the first button a new DOM is loaded, so click on the second (and third …) will end with StaleElementReferenceException. You need to get all the href values first and then try them one by one. Just tried on web bbc.com with this code: package navi; import java.util.ArrayList; import java.util.List; import org.junit.After; … Read more
If you’re trying to use findViewById in Fragment, first of all make sure you’re using onCreateView() and you’re returning the view at the end. See the differences in here: Difference and uses of onCreate(), onCreateView() and onActivityCreated() in fragments Here is an example for that: @Override public View onCreateView(LayoutInflater inflater, ViewGroup parent, Bundle savedInstanceState) { … Read more