java

[Solved] passing json reply from webservice to variables

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You are getting response in JSONObject and you are trying to get it in JSONArray.. thats why you are getting error.. Try this way… try { JSONObject result = new JSONObject(response); if(data.has(“ValidateLoginResult”){ JSONArray array = result.getJSONArray(“ValidateLoginResult”); for (int i = 0; i < array.length(); i++) { JSONObject obj = array.getJSONObject(i); String ErrorMessage= “”+obj.getString(“ErrorMessage”); String PropertyName= … Read more

[Solved] required: boolean found: int 1 error

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Did you ever initialize numberOfTries? Try changing this: for (numberOfTries=0; numberOfTries = 4; numberOfTries++){ To: for (int numberOfTries=0; numberOfTries <= 4; numberOfTries++){ 2 solved required: boolean found: int 1 error

[Solved] Password input program [closed]

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You have a logic error in your compare() method. When you use one = you are doing an assignment, not a comparison: if (passCompare = true) // assigns true to passCompare and always evaluates true return true; else return false; More fundamentally, don’t reinvent the wheel. The String class already has a perfectly good way … Read more

[Solved] How can I add one month to change into the milliseconds?

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I suggest: First, instead of your variables (fields?) year, month, day, hours and minutes just declare private LocalDate date; private LocalTime time; private long milliseconds; (Keep the milliseconds variable since you will want to have your result here.) In onDateSet assign a value to date in this way: date = LocalDate.of(selectedYear, selectedMonth + 1, selectedDate); … Read more

[Solved] Unable to scrape data from Internet using Android intents

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Have you considered using an http framework for Android instead? It’s a lot less code and also runs the requests in the background. This example uses the loopj async client build.gradle: compile ‘com.loopj.android:android-async-http:1.4.9’ compile ‘cz.msebera.android:httpclient:4.4.1.2’ Test code: @Test public void parseHttp() throws Exception { AsyncHttpClient client = new AsyncHttpClient(); final CountDownLatch latch = new CountDownLatch(1); … Read more

[Solved] java.AWT – setSize() method

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Take this code import java.awt.Frame; public class AwtPrac { private static void init(){ Frame fm = new Frame(“Java Programm”); fm.setTitle(“AwtPrac”); fm.setSize(300,300); fm.setVisible(true); } public static void main(String[] args) { init(); } } 3 solved java.AWT – setSize() method

[Solved] Need an If Statement syntax explanation [closed]

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The indexOf method returns the index of the searched string. If the string is not found, it returns -1. That’s why you have that comparison, it’s to make sure that the searched string is found. 1 solved Need an If Statement syntax explanation [closed]

[Solved] How to parse date string into integer variables? [duplicate]

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String date = “13-08-2016”; String[] values = date.split(“-“); int day = Integer.parseInt(values[0]); int month = Integer.parseInt(values[1]); int year = Integer.parseInt(values[2]); You can use String.split(String regex) method to parse the date to array of String then convert each value to int. JavaDoc: public String[] split(String regex) Splits this string around matches of the given regular expression. … Read more

[Solved] Java StringBuffer cannot print out apostrophe

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Tom, The problem is that one string is longer than the other one. import java.util.Scanner; public class Main { public static void main(String[] args) { Scanner sc = new Scanner(System.in); String elso = sc.nextLine(); String masodik = sc.nextLine(); String longestString = elso; String shortestString = masodik; if (shortestString.length() > longestString.length()){ shortestString = elso; longestString = … Read more