java

[Solved] Android Studio (Java) Replace function [closed]

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In Android, inside a Layout you insert an EditText, it’s that text field you wanted where you can write text into it and also listen to text changes so you can do those manipulations you were talking about. Create a TextWatcher and add it to the EditText using addTextChangedListener(TextWatcher variable) new TextWatcher() { @Override public … Read more

[Solved] if an override method returns something, what that means , how this can be Usefull? [closed]

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Interfaces let you define methods that will be common to a group of classes. The implementation of the interface can be different for each class, and it’s up to those classes to independently implement what that methods do. interface Animal { // Define the interface Boolean canBite(); } class Dog implements Animal { // Define … Read more

[Solved] Sorting List of List of Long [closed]

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Use element wise comparator Compare 2 lists by compare in increasing order of index location if any non-zero value is found, return the result else compare the size of the lists sort the lists using this comparator logic Use per index comparator chain. Based on WJS’s approach Compute the maximum list size across all of … Read more

[Solved] If I have a String containing for example “234” and I want to print it out as “£2.34” How do I do this in Java? [duplicate]

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You could use the length of the string as the determinant of whether to format the string using ‘p’ or ‘£’, then use .substring() to get the individual parts of the string (the euros and cents) Here’s an example: if(string.length() < 3) { System.out.println(string+”p”); } else { System.out.println(“£”+string.substring(0, string.length()-2)+”.”+string.substring(string.length-2)); } What this does is: If … Read more

[Solved] Fitlering words

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You had the right idea with int e = 0 in your earlier comment. for (int i=0; i<towns.length; i++){ if(!towns[i].contains(“p”)){ int e=0; for (int j=0; j<towns[i].length; j++){ if(towns[i].charAt(j) == ‘e’ || towns[i].charAt(j) == ‘E’){ e++; } } if(e>1 && e<5){//This is assuming you don’t want to print cities with more than 4 E’s System.out.println(towns[i]); } … Read more

[Solved] Java, method not applicable for arguments

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change method declaration to private static void mysecondclass(String string, String string2, String string3){ System.out.println(string+” “+string2+” “+string3); } a circular bracket is missing in your code and also remove the semicolon after that. 6 solved Java, method not applicable for arguments

[Solved] Java never declares access level of variables in methods whether static or not [closed]

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Because it doesn’t make sense. Variables declared in a method are local to the method; i.e. they can’t be accessed outside the method. Why and how could these variables be modified outside the method? Code outside the method doesn’t even know of them, so you don’t need to protect them from outside code. solved Java … Read more

[Solved] Alphanumeric increment algorithm in JAVA [closed]

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Here’s 3 solutions: the first two are somewhat arithmetic incrementations while the third is more a character manipulations. The 3 implementations all pass the same unit tests: assertEquals(“1DDA01A”, MyClass.increment(“1DDA00Z”)); assertEquals(“1A9AV00”, MyClass.increment(“1A9AU99”)); assertEquals(“AFH00”, MyClass.increment(“AFG99”)); assertEquals(“A2GF24”, MyClass.increment(“A2GF23”)); assertEquals(“ABAA0000”, MyClass.increment(“AAZZ9999”)); assertEquals(“11AB0A”, MyClass.increment(“11AA9Z”)); First: public static String increment(String number) { Pattern compile = Pattern.compile(“^(.*?)([9Z]*)$”); Matcher matcher = compile.matcher(number); String … Read more