java

[Solved] Longest monotonic subsequence algorithm NOT longest increasing algorithm

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try this one: import java.io.BufferedReader; import java.io.InputStreamReader; public class Rozwiazanie { public static void main(String[] args) { try { BufferedReader br = new BufferedReader(new InputStreamReader(System.in)); String[] splittedLinia = br.readLine().split((char) 32 + “”);//moglaby byc ” ” ale tak na wszelki wypadek nie ma chuja zeby sie popierdolilo teraz nawet na linuxie int aktualnyWyraz = Integer.parseInt(splittedLinia[0]);//uwaga jakby … Read more

[Solved] Using string.replace() [closed]

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Do not specify the class String before your string literal. filename.replace(“*”, wildcard) And nextLine() is an existing method in the Scanner class. scannextLine() isn’t. String wildcard = scan.nextLine(); 4 solved Using string.replace() [closed]

[Solved] How to handle configuration properties in Java [closed]

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Leverage standard Java Properties class. Create a properties file, i.e. conf.properties and load it. #conf.properties: key=value #code Properties conf = new Properties(); conf.load(new FileInputStream(new File(“conf.properties”))); conf.getProperty(“key”); // returns “value” solved How to handle configuration properties in Java [closed]

[Solved] Java logic operators [closed]

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No, that would be a compilation error since it is parsing as if ((clickedButton == button0) || (button1) || (button2) … and buttons are not booleans. You must do: if (clickedButton == button0 || clickedButton == button1 … But an array would be much cleaner, instead of having nine separate button variables. Then you could … Read more

[Solved] System.out.println – Java

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Introduction System.out.println is a Java statement that is used to print a line of text to the console. It is one of the most commonly used statements in Java programming. It is a part of the java.io package and is used to print a line of text to the console. It is a very simple … Read more

[Solved] System.out.println – Java

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You can if you import static like import static java.lang.System.out; then you can do public static void main(String[] args) { out.println(“Hello, World”); } 2 solved System.out.println – Java

[Solved] Discrepancy in Java Calendar set Day Of Month vs Get Day Of Month

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TL:DR LocalDateTime ldt = LocalDateTime.of( reminder.getReminderYear(), reminder.getReminderMonth() + 1, // Add one to adjust from zero-based counting. reminder.getReminderDayofMonth(), reminder.getReminderHour(), reminder.getReminderMinute() ); java.time I suggest you put an end to using the very old and long outmoded Calendar class. Today we have so much better in java.time, the modern Java date and time API also known … Read more

[Solved] Code compiles and executes, but does not print anything

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Option A : Change your while into an if statement : if(i<input3) { minstones= minstones + arrK[i]*(n-i); } Option B : or increment i (i++) but I don’t this that’s what you want while(i<input3) { minstones = minstones + arrK[i]*(n-i); i++; } 0 solved Code compiles and executes, but does not print anything

[Solved] How to read and update SQLite database using ListView in Android?

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Here Is Your Edited Working Code MainActivityChampagne.java package android.application.project.planes; import java.util.ArrayList; import android.content.ContentValues; import android.content.Context; import android.database.Cursor; import android.database.sqlite.SQLiteDatabase; import android.database.sqlite.SQLiteOpenHelper; public class MainActivityChampagne { public static final String KEY_NAME = “title”; public static final String KEY_NOTES = “lastcall”; private static final String DATABASE_NAME = “Champagnedb”; private static final String DATABASE_TABLE = “champagneTable”; private static … Read more

[Solved] Increment operator java [closed]

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Because you’re using the post-increment operator ++ that occurs after the variable to increment. Its value is the current value of the variable, and the increment happens afterwards. JLS 15.14.2 covers this: [T]he value 1 is added to the value of the variable and the sum is stored back into the variable. and The value … Read more

[Solved] Convert image to binary to apply Image Steganography [closed]

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If I understand the question correctly, you want to get the single bytes of the jpg-file, which can be read with a DataInputStream: File imageFile; DataInputStream dis = new DataInputStream(new FileInputStream(imageFile)); int input = dis.read(); dis.close(); input then holds the first byte of the file, if you invoke read again (before dis.close()), you can read … Read more

[Solved] Perfect numbers. Something wrong

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The if (sum == number) check needs to be done outside the loop. Otherwise you might pick up numbers such that the sum of a subset of divisors equals the number. In fact, 24 is one such example since 1+2+3+4+6+8=24. Your code prematurely concludes that 24 is perfect, despite it also being divisible by 12. … Read more