var purchaseValue = 7000; var children = 10; var discount = 0; if(purchaseValue >= 5000){ if(children > 4){ discount = 22; } else if(children > 7){ discount = 30; } } else if(purchaseValue <= 2500){ discount = 10; } var amount = (discount/100) * purchaseValue; 4 solved Using nested if statements ( Help ) [closed]
If its a c# code then you can use contains to check the stageID if(stageID.Contains(1)) { //your code } else if(stageID.Contains(2)) { //your code } else { // your code } if its a SQL code DECLARE stageID number(3) := 100; BEGIN — check the boolean condition using if statement IF( stageID < 20 ) … Read more
It is because the if statement is not indented properly and its condition is not specified as a string ‘help’: while 1: userCommand = input(‘Type a command (type \’help\’ for syntax): ‘) if userCommand == ‘help’: print (‘flight: this command will be used to list a flight’) break solved How do I add ‘if’ commands … Read more
I agree with others that there are many ways to simplify your code, but if you just want to simplify the if statement you can do this: if (!(x.contains(“6”)) && A1*B1*C1==6 && A2*B2*C2==6 && A3*B3*C3==6 && A1*A2*A3==6 && B1*B2*B3==6 && C1*C2*C3==6) The reason this works is that the only bags of three positive integers that … Read more
You should do it with a switch : public static void main(String args[]) { System.out.println(“Enter 1 to Add, 2 to Subtract, 3 to Divide, or 4 to Multiply”); int x = keyboard.nextInt(); switch(x){ case 1: System.out.println(“Enter an integer”); int num1 = keyboard.nextInt(); System.out.println(“Enter another integer”); int num2 = keyboard.nextInt(); System.out.println(“The sum of the numbers equals … Read more
I assume, that you have at least some knowledge of computer programming in some other language then Objective-C. I will talk about this line, but the same problem occurs in several lines in your code if(NSInteger >= 4) You compare the type NSInteger with a number (4). I assume you want to compare a variable … Read more
You seem to have confused if and while. if only runs at most once. while will run any number of times until the condition is false. while num > 2: … 2 solved Did not understand the outputs [closed]
This: if(fare == -40){ char desc[50] = “Ouch! Cold either way!!”; } opens up a new scope, with a new local variable called desc, that “shadows” the one in the surrounding scope. This variable is initialized to the string, then thrown away as the scope exits. The variable of the same name in the parent … Read more
Try the following: if (Group == ‘Customer’) { if(Status != ‘Agreement’) { cell.css (‘color’, ‘blue’); } } else if (Group == ‘Non-customer’) { if (Staus == null) { cell.css (‘color’, ‘green’); } else if (Status != ‘Agreement’) { cell.css (‘color’, ‘yellow’); } else if (Status != ‘Not declared’) { cell.css (‘color’, ‘purple’); } } solved … Read more
parseInt(number, 10)= b; So you are saying to assigning b to parseInt. You have it reversed. var b = parseInt(number, 10) You have the problem in multiple places. solved I get an invalid left hand side in assignment with my code [closed]
Ok your question seems to be particularly unpopular… just for info, have a look at http://en.wikipedia.org/wiki/Operators_in_C_and_C%2B%2B The operator you are looking for is && but I should not tell you this since in fact as downvotes testify… your question is a bit lazy! I also know that sometimes when you are a noob it can … Read more
I can’t tell you what to do to make it “work”, since your desired result is pretty unclear, but a number of problems in your code jumped out at me as I skimmed it top to bottom. Some will still run but give results you aren’t expecting, but at least one problem will cause an … Read more
First of all, make sure your code is properly and regularly indented, as that is how Python decides what is and isn’t included in the if statement. Second, you must add a colon after the condition or it will be a syntax error. Your code should look like this: print(“Whose team are you on?”) die … Read more
You’re setting the string userAnswer = “”; in your declaration. but.. in your if you’re checking it on if (userAnswer != null) but… it’s never null You should check if (userAnswer != “”) Because if a string has the value null isn’t the same as an empty string “” 4 solved If Statement Not working … Read more
You just need to fix the indentation r = 0 while r<15: hit = str(input(“””A1 A2 A3 A4 A5\n\nB1 B2 B3 B4 B5\n\nC1 C2 C3 C4 C5\n\nD1 D2 D3 D4 D5\n\nE1 E2 E3 E4 E5\nThis is the board. Pick any co- ordinate you want to fire on: “””)) if hit in (“A2”, “a2”): print(“You hit … Read more