Preprocessor directives are interpreted before compiling your program. So VAR has no knowledge of a and b. See C preprocessor on Wikipedia. Instead, you could create a macro that takes parameters, like this: #define VAR(a,b) (a | b) …and use it like that: #if (VAR(a,b) != 0) You would have to adapt your program, since … Read more
I can see a couple of errors in your code. First, as Pete Becker noted (and Lightness Races in Orbit refined), total isn’t initialized, so its value is indeterminate. It could even be an invalid representation of a floating point number (e.g. a NaN ) and it isn’t for sure a valid starting point for … Read more
I figure this out finally. Assignment Expressions in Python 3.8 is what I am looking for. if name in name_dict: info = name_dict[‘name’] ## <– may be a more complicated function if info == ”: info = input(“Input your info: “) else: info = input(“Input your info: “) Can be turn into: if (name not … Read more
When you’re using Scanner.nextInt() the input is expected to be an integer. Inputting anything else, including a real number, will throw an InputMismatchException. To make sure invalid input doesn’t stop your program, use a try/catch to handle the exception: int num; try { num = sc.nextInt(); // Continue doing things with num } catch (InputMismatchException … Read more
This is perhaps a bit of an aside, but you could greatly simplify this by saying: while True: guess = input(“Guess one letter in the word!: “) if guess in l: print(“Correct”) else: print(“Incorrect”) This would also have the side effect of allowing you to change your word to guess to one of a different … Read more
It does not crash, it doesn’t even compile. The following is probably what you want: var isPrime = true var number = “Four” var i = 2 if let numInt = Int(number) { while i < numInt { if numInt % i == 0 { isPrime = false } i += 1 } } else … Read more
noob here, trying to help. From what I understand there are 3 possibilities. Can’t enter (younger than 18 years old) May enter but can’t get a drink (younger than 21 but still over 18) Can enter and have a drink (over 21 years old) Therefore I think that it would be best to minimize the … Read more
You’re decrementing i twice: once inside the if-statement, once every time in the while loop. Hence, when the if statement evaluates to True, i will be decremented by 2 in total, and you will skip past some values of i. A quick test shows that, indeed, i == 194 is skipped: i jumps from 195 … Read more
def attempt_function(): number_of_attempts = 0 saidpassword = “” while saidpassword != password: number_of_attempts + 1 saidpassword = input(“the password you entered is incorrect, please try again\n”) if number_of_attempts > 3: print(“You have entered the wrong password too many times, please try again later”) break saidpassword = input(“the password you entered is incorrect, please try again\n”) … Read more
Since playerSelections and colorSequence are arrays, your the condition gameObject.playerSelections === gameObject.colorSequence tests that the array references are equal, not the contents of the arrays. You need to check that each element of the array is equal: How to check identical array in most efficient way? 1 solved Javascript program is not recognizing an if … Read more
The first one would have to look at the value of process_checking twice, so performance would be (very very negligibly) worse. And of course your assumption about the “0” and “1”, the first one has to check for “1”, which is a little extra work. The real difference is readability. The second one is much … Read more
I have found the optimal solution: To use def(x) it’s the best solution now. (loop) list = [‘enfj’,’enfp’,’entj’,’entp’,’esfj’,’esfp’,’estj’,’estp’,’infj’,’infp’,’intj’,’intp’,’isfj’,’isfp’,’istj’,’istp’] def get_label(path, list=list): for psychoType in list: if psychoType in path: return psychoType data[“psychoType”] = data[“path”].apply(get_label) solved Python „stack overflow” (104 if statements). Is def(x) the only solution to optimise code?
“Whenever i choose 1 as my parameter, i enter 3 as my instruction classes however i am unable to input the CPI of class 3 or even the instruction count of class 3. Once i input the CPI and instruction count of class 2 it ends.” This is because you tell it to. Here: for(a … Read more
When you don’t have any POST data, your variable $_POST is still an empty array, so this means that it is set. If you want to do exit, you should check $_POST variable with empty() function. solved Hello world, why this code doesn’t work? [closed]
The reason for that is simple – in java every condition must be resolved as a boolean value (true of false) while in c / c++ false is 0 while true is anything else… 1 solved Why does the if statement “if(1)” give error in Java but it holds true in C++?