[ad_1] Setting the position to relative doesnt necessarily dictate order in terms of horzontal vs vertical placing. This is the difference between block level and inline elements. Block level elements (e.g. div) display on a new line by default, inline elements (e.g. span) appear on the same line, if the available width allows it. You … Read more
[ad_1] .container-main-fixedscroll needs to be height: calc(100% – 45px) because of the height of your header html, body { height: 100% } body { margin: 0px; font-family: repub; color: white; } .container-main-left { float: left; width: 15%; min-height: 100%; background-color: red; display: inline-block; line-height: 300%; } .container-main-right { float: right; width: 15%; min-height: 100%; background-color: … Read more
[ad_1] Let me give a snippet of code that i use function updateAutoSrch() { $(“#searchpro”).autocomplete({ source: function( request, response ) { $.ajax({ url: “search”, data: {proname: proname}, dataType: “json”, success: function( data ) { response( $.map( data, function( item ) { return { label: item.user_name, value: item.user_name, userid: item.user_id, profile_image_path: item.profile_image_path } })); } }); … Read more
[ad_1] This line does not make sense. $empid = $_POST[“EMPLOYER ID”]; A post variable name cannot contain a space. [ad_2] solved No response to update query in oracle [closed]
[ad_1] You would need to: Extract the data from the div using JavaScript Include it in your POST request. Catch and handle the request in PHP to store it in the Database. Example: This is a single PHP file sample (without full page refresh), but you may need to change the part DATABASE_NAME_HERE and also … Read more
[ad_1] Try CSS3 column-count div { -webkit-column-count: 2; /* Chrome, Safari, Opera */ -moz-column-count: 2; /* Firefox */ column-count: 2; } <div> <input type=”radio” name=”group”>Option 1 <br> <input type=”radio” name=”group”>Option 2 <br> <input type=”radio” name=”group”>Option 3 <br> <input type=”radio” name=”group”>Option 4 <br> <input type=”radio” name=”group”>Option 5 <br> <input type=”radio” name=”group”>Option 6 <br> <input type=”radio” name=”group”>Option … Read more
[ad_1] You cannot put <div> in the head section, here is the modified code: <!DOCTYPE html> <html> <head> <style type=”text/css”> #bottom{ width:70px; color:green; align-content:center; } </style> <title></title> </head> <body> <div id=”heading” title=”topbar”> <h2>Welcome to our website</h2> </div> <div id=”bottom” title=”bottombar”> <h2>Welcome to our website</h2> </div> </body> </html> You forgot the closing semi-colons in the css … Read more
[ad_1] You have to cut your template into components and replace class attribute with className. var MyComponent = React.createClass({ render: function() { return ( <div className=”my-class”> Hello, world! </div> ); } }); ReactDOM.render( <MyComponent />, document.getElementById(‘content’) ); Take a look at official tutorial But I strongly recommend you to read the documentation first and only … Read more
[ad_1] Since you haven’t specified your problem, Here is the basic mysqlcode for your problem. SELECT column_name FROM table_name ORDER BY column_name ASC \ DESC; ORDER BY ASC \ DESC is responsible for making the order. other things are usual mysql elements 7 [ad_2] solved MYSQL sort by desc or asc
[ad_1] I think you’re asking how to put that piece of code inside HTML…? If so, it’s easy. Put <script> tags inside your html: <script> function url() { var x = window.location.pathname; if (x==”/index/index.php”) { } } </script> And your JavaScript code will work. If you’re saying you need to write your whole page in … Read more
[ad_1] <?php if (get_post_meta($post->ID, ‘Rental’, true)) { ?> <li style=”padding:3px 10px; line-height: 18px; height:34px”> <strong><?php _e(‘Rental Potential / Actual’, ‘spanglishwebs’) ?>:</strong> <?php $priceWithoutFormat = get_custom_field(‘Rental’); $priceWithFormat = number_format($priceWithoutFormat, 0, ‘,’, ‘.’); echo $priceWithFormat; ?>€/Annual </li> <?php } else { ?> <li>Rental Potential / Actual: N/A</li> <?php } ?> Try if it works, your code is … Read more
[ad_1] try this $un_check = mysql_query(“SELECT Username FROM users WHERE Username=”POSTVALUE””); if(mysql_num_rows($un_check) >0) { echo “Username is taken”; } else{ // Username Free } 2 [ad_2] solved Database not checking if username is free [closed]
[ad_1] You should really have looked into jQuery documentation as this is all basic stuff, but I am feeling generous: The following subscribes to the “DOM ready event”, so that your code will only run after the DOM elements are all loaded: $(document).ready(function() { Then it runs an Ajax HTTP GET request to the specified … Read more
[ad_1] The problem is with your data-source. Check the Data-Source means in the Select Query in Database or In-Line Query from which you are filling the DataTable or DataSet. it must include Image Column. [ad_2] solved How to write the databinder into the image tag in datalist
[ad_1] You can’t make HTML directly interacting with database. You should create server-side application, which answer queries generated by HTML forms, JS queries, etc. I am PHP developer, I like this language, so I recommend you using it in your solution. You can read about connecting PHP to MySQL database here: http://www.w3schools.com/php/php_mysql_connect.asp There you have … Read more