[Solved] array function C++

bool equivalent(int a[], int b[], int n) { int i=0, j=0, count=0; // This condition fails immediately because the values are equal while (a[i] != b[j]) { // For this reason neither count nor j are incremented count++; j++; } for (int i=0; i<=n; i++) // This condition succeeds immediately because these values are equal … Read more

[Solved] How to wrap php code inside a function? [closed]

It might help, little format,and use variable to return entire html if needed to make it function, <?php function formatOutput() { $term_slug = get_query_var( ‘term’ ); $taxonomyName = get_query_var( ‘taxonomy’ ); $current_term = get_term_by( ‘slug’, $term_slug, $taxonomyName ); $args = array( ‘child_of’ => $current_term->term_id, ‘hide_empty’=>false); $terms = get_terms( ‘tagportifolio’, $args); $assoc = taxonomy_image_plugin_get_associations(); $output=””; if … Read more

[Solved] What is this C function doing?

This code accepts a decimal value and prints the hexadecimal representation. Try it out yourself In C we can use the %x (%X) format specifier flag to printf to do it for us: printf(“%X”, 16); // 10 printf(“\n”); printf(“%X”, 42); // 2A If you’re using a C++ compiler, we can instead use the std::hex stream … Read more

[Solved] Loop: Results to be updated via += if on the same date, otherwise write next line

You can use DataFrame.append and then group by the column you want to use as an index. Let’s say that total_df is the table to which you want to add new rows, new_df is the table containing those new rows and date is the column to be used as index. Then you can use: total_df.append(new_df).groupby(by=’date’).sum() … Read more

[Solved] python Regular expression [closed]

I think this is what you’re after: file = open(“demo.txt”,”r”) text = file.read() def find(info,text): match = re.findall(info + “+\w+\d+”,text) if match: print(match) else: print(“Not found!”) # This is how you call the function find(“whatever info is supposed to be”,text) 3 solved python Regular expression [closed]