You have to add attribute , ” required ” to all the input fields so that an error message will be displayed when one is empty!! To check if the answer is correct, you can use php! $name=$_GET[“name”]; $email=$_GET[“email”]; $ans=$_GET[“ans”]; if($ans==’correct’){ // you can use mail command here header(“location:correct.php”); }else{ header(“location:incorrect.php”); } solved php radio … Read more
Are you simply asking how to validate a set of radio buttons? Since you’ve shown no code, all I can show you is how you would validate a set of radio input‘s with the plugin. Then you would dynamically add/remove rules from the corresponding inputs using the built-in rules method. Again, I’d need to see … Read more
The problem I had was that there is 4 submit buttons each with different name tag so the session will only store the last input button and will make it functional but for the others it will only refresh the page with no different because they are not being controlled by php code so to … Read more
jQuery, or javascript in general, can’t really connect directly to a database like you are describing. If you have an endpoint to hit, then jQuery (or vanilla javascript, really) could just fire a request to that endpoint with the specific data: $(‘input:file’).on(‘change’, function(event) { $.ajax({ url: ‘/path/to/endpoint’, type: ‘post’, data: { filename: $(this).val() } }); … Read more
This will give you the total tax : parseInt(totaltopay.value)*0.19/1.19 1 solved Javascript calculate 19% taxes from parseFloat value total to pay
Please use below code to fix your problem <?php if(empty($_POST[‘username’])){ $username_error = “Please Input Username”; }else{ if( 6 > mb_strlen($_POST[‘username’]) || 20 < mb_strlen($_POST[‘username’])){ $username_error = “username must be at least 6 characters.”; }else{ $username = $_POST[‘username’]; $sql = “SELECT members.username FROM members WHERE username=””. $username.”””; $res = mysql_query($sql); if($res && mysql_num_rows($res) > 0){ $username_exists … Read more
Problem is when u click on second form data in url will be contain just elements from that form not from first form so if u want in second form get information about typeAnag u need to create hidden input in second form…. 0 solved How to store variable value after clicking “Submit”?
you have to get the choice from the url by GET method. <?php include “../areashoppers/includes/cs_functions.php”; $choice = $_GET[‘choice’]; $sql = “SELECT distinct town FROM oic_areas_full WHERE region=’$choice’ ORDER BY town ASC”; $st = $sc_conn->query($sql); while ($r = $st->fetch()) { echo “<option>” . $r[‘town’] . “</option>”; } ?> 3 solved Populate second select list based on … Read more
Why do you need a new form class for each country? The idea of a class is that it holds common behaviours. A form is a class. just instantiate an instance of the class with the data that it needs to display. Create a data class to encapsulate the data that the form shows (like … Read more
This is most likely a permission issue. Check write permission with is_writable or enable error output with ini_set(‘display_errors’, true); Change permissions for data.txt accordingly. 0 solved Save html form data to a txt file using php
Something like this, maybe? function addNumbers(){ var input1 = Number(document.getElementById(‘input1’).value); var input2 = Number(document.getElementById(‘input2’).value); document.getElementById(‘output’).value = input1 + input2; } <input type=”text” onkeyup=”addNumbers()” id=”input1″ placeholder=”enter a number”><br /> <input type=”text” onkeyup=”addNumbers()” id=”input2″ placeholder=”enter another number”><br /> <input type=”text” id=”output” disabled> 1 solved html forms that update in real time [closed]
This is because you are using ; in every if statement instead of if { .. } statements try this code <?php if (isset($_POST[‘your_name’])) { $your_name = $_POST[‘your_name’]; } if (isset($_POST[‘your_email’])) { $your_email = $_POST[‘your_email’]; } if (isset($_POST[‘subject’])) { $subject = $_POST[‘subject’]; } if (isset($_POST[‘message’])) { $message = $_POST[‘message’]; } $to = “email.co.uk”; $subject = … Read more