Is there another solution for this situation without using braces? That is the wrong question. The real question is: is there ever a reason to NOT use braces? NO. Just use braces. Your colleagues, and future-you, will thank you later. 1 solved Is this the most elegant/safe/recommended solution for this situation?
The problem is that replace(“st”, “”) also removes the st ending of August, resulting in the input string seen in the error message. To handle this, you need to make sure the st suffix is right after a digit, so it’s part of the day value. You also need to handle all of 1st, 2nd, … Read more
$times_array = array(); $times = array(“10:30″,”11:00″,”9:00”); foreach($times as $time){ $times_array[strtotime($time)] = $time; } ksort($times_array); print_r($times_array); solved How to change format of a number in sql?
Using datetime function from datetime import datetime date = “12-01-2011” datetimeobject = datetime.strptime(date,’%d-%m-%Y’) newformat = datetime.strftime(datetimeobject,’%Y-%m-%d’) print(newformat) 0 solved I cant relocate or reverse string python [closed]
Probably the closest short of looping and building a string, is something using pprint.pformat, such as: >>> from pprint import pformat >>> my_dct = dict( k1=1, k3=3, k2=2,) >>> print(‘my_dct = {{\n {}\n}}’.format(pformat(my_dct, width=1)[1:-1])) my_dct = { ‘k1’: 1, ‘k2’: 2, ‘k3’: 3 } solved write() file by inserting dict in specific key order and … Read more
Using a regex would work like this: import re regex = r’\d-\d{4}-\d{4}-\d’ preg = re.compile(regex) s1 = ‘9-9715-0210-0’ s2 = ‘997-150-210-0’ m1 = preg.match(s1) m2 = preg.match(s2) if m1: print(‘String s1 is valid’) else: print(‘String s1 is invalid’) if m2: print(‘String s2 is valid’) else: print(‘String s2 is invalid’) You can try the code at … Read more
You should use K format specifier, since it represents timezone offset string format = “yyyy-MM-ddTHH:mm:ss.FFFK”; or zzz, which means signed timezone offset string format = “yyyy-MM-ddTHH:mm:ss.FFFzzz”; You also might change DateTimeStyles to AdjustToUniversal to get 5/14/2020 1:37:49 PM date, otherwise it’ll be adjusted to local time DateTime d; DateTime.TryParseExact(f, format, CultureInfo.InvariantCulture, DateTimeStyles.AdjustToUniversal, out d); 0 … Read more
I think this is more of a subjective question. I would argue that its ok following the principle of duck typing: If it looks like a duck, swims like a duck, and quacks like a duck, then it probably is a duck. If you are looping through an array of strings and they all have … Read more
Standard PNGs don’t support editing. Simplifying it a bit, they are just what you said they are: losslessly compressed bitmaps (vs JPGs, which employ lossy compression, or GIFs which are also bitmaps, but only support up to a 256 color palette). Fireworks PNGs contain a special header and extra data that allows them to retain … Read more
Try this should help: $datedb = “2018-03-01 11:54:33”; $date = date(‘d-m-Y’, strtotime($datedb)); echo $date; // will print 01-03-2018 And read about date() function of php: http://php.net/manual/en/function.date.php; https://www.w3schools.com/php/func_date_date.asp 0 solved SQL Timestamp format in PHP [duplicate]
us is a variable of type (class) NumberFormat. getCurrencyInstance() is a static method (a method of the class, not of an object). So this method is not related to a object. But this method generates an object of class NumberFormat (a kind of factory), that is stored in the variable us. now that you have … Read more
Unless the code you posted is within a script tag inside a blade file, it is not possible to use Carbon inside of an external JavaScript file. 8 solved i want to use carbon format time with jquery but I don’t nkow how to convert jquery data to php [closed]
Use the modern Java date and time classes for everything that has got to do with dates or times. DateTimeFormatter usFormatter = DateTimeFormatter.ofLocalizedDate(FormatStyle.SHORT) .withLocale(Locale.US); System.out.println(date.format(usFormatter)); DateTimeFormatter deFormatter = DateTimeFormatter.ofLocalizedDate(FormatStyle.SHORT) .withLocale(Locale.GERMANY); System.out.println(date.format(deFormatter)); This will print something like 6/27/17 27.06.17 It’s not exactly the formats you asked for, but it’s the formats Java thinks are appropriate for … Read more
using php try like this $month=”JAN-2014″; echo date(‘m’, strtotime($month)); 1 solved How to get month in number from date in “JAN-2014” format?
Kindly go through following R console code snippet: > dates <- c(“10/23/16”, “10/24/16”) > dates [1] “10/23/16” “10/24/16” > Dates <- as.Date(dates, + format = “%m/%d/%y”) > Dates [1] “2016-10-23” “2016-10-24″ Hope it works for you! solved Fix incomplete character string for year “2016” from “0016” in R [closed]