[ad_1] df <- X – Y plyr::ldply(1:nrow(df), function(x) data.frame( min=min(df[x,], na.rm=T), max=max(df[x,], na.rm=T))) 1 [ad_2] solved How to write a function in R to calculate the min/max difference between two dataframes?
[ad_1] just replace the condition of the there loops with 26. Now the exception index out of bound will not occur public class SuggestingAppNames { public static void main(String[] args) { System.out.println(“the possible outcomes are”); String a = “A,B,C,D,E,F,G,H,I,J,K,L,M,N,O,P,Q,R,S,T,U,V,W,X,Y,Z”; String d[] = a.split(“,”); String b = “A,B,C,D,E,F,G,H,I,J,K,L,M,N,O,P,Q,R,S,T,U,V,W,X,Y,Z”; String e[] = b.split(“,”); String c = “A,B,C,D,E,F,G,H,I,J,K,L,M,N,O,P,Q,R,S,T,U,V,W,X,Y,Z”; … Read more
[ad_1] Just use a regular for loop to iterate over all arrays at once: String[] item ={“[1]hotdog”, “[2]eggpie”,”[3]menudo”,”[4]pizza”,”[5]lumpia”}; int[] cost = {5, 10, 15, 20, 25}; int[] selling = {10,15,20,25,30,}; int[] qty = {2,4,6,8,10}; for (int i = 0; i < item.length; i++) { System.out.println(” ” +item[i]+”\t”+cost[i]+”\t\t”+selling[i]+”\t\t”+qty[i]); } I would recommend putting all of these … Read more
[ad_1] in your image is in quotes, is an f-string, but they forgot to add the f year = [2016,2017,2018,2019,2020] for i in year: rtx_price = (data.loc[f'{year}-07-31′, ‘RTX’]) 6 [ad_2] solved Python for loops with an array [closed]
[ad_1] OK, so assuming you want to store the results in c, with dims 256, 50, do something like: for(int i = 0; i < 256; ++i) for(int j = 0; j < 55; ++j) { c[i][j] = compute_correlation(matrixA, i, matrixB, j); } with compute_correlation a simple for loop that will compute the value according … Read more
[ad_1] I would probably consider doing this another way… Have an empty hashmap<String sub, int multiplier> Read in the name Generate the subname Fetch from or create subname in hashmap If new, set multiplier to 1 If exists, increment multiplier Return String.format(“%s%3d”, subname, multiplier x 5).toUpperCase() I would give you code but writing the above … Read more
[ad_1] You never call your method “forloop()”, that’s the reason why there’s nothing printed. NewbieJavaDeveloper’s answer is a good one. But if you want to pactice “method and return”, here is another answer: import java.util.Scanner;//import scanner so user can input class arrays { public static void main(String[] param) { String[] animals = arrays(); forloop(animals); System.exit(0); … Read more
[ad_1] If you’re simply looking for its index in the loop: <textarea name=”description{{ loop.index }}”> Here’s the docs. 1 [ad_2] solved How to attach counter variable on field in twig file?
[ad_1] I tried to run that and my outputs for r1 and r2 are qwdaweqwe asdas–sd (two spaces) and basically it is what the code should be doing. But if I get your intention right, you want to work with those empty strings. Then you should be feeding your function with different numbers, because array … Read more
[ad_1] This kinda works. I can think of a couple of cases where something like this would break, like if the arrays were like {9,9,9} and {9,9,9}, result would be {9,9,8} instead of {1,9,9,8}. It’s a minor fix that is being left as an activity to the reader. public static void main(String []args){ int[] number1 … Read more
[ad_1] Assuming that sorted_indices contains only integers: tmaxima = [t[i] for i in sorted_indices] ag_maxima = [a_g[i] for i in sorted_indices] [ad_2] solved how to turn this python lines code into a list comprehension?
[ad_1] The first one will stop straight after the first iteration, because of the else statement. return breaks the loop. It will only test if the number you give is even or odd num%2 == 0. The second one will stop only if the condition is verified (again, the return breaks the loop), or at … Read more
[ad_1] from itertools import chain l = [[‘password’, ‘_rev’, ‘_id’, ‘username’], [‘password’, ‘_rev’, ‘_id’, ‘username’, ‘name’], [‘password’, ‘_rev’, ‘_id’, ‘username’],[‘password’, ‘_rev’, ‘_id’, ‘username’,’country’]] list(set(chain(*l))) Output – [‘username’, ‘_rev’, ‘_id’, ‘name’, ‘password’, ‘country’] [ad_2] solved merge list of nested list to a single list which has lakhs of data python [duplicate]
[ad_1] Just use a if condition. if (i == 1) { animal = “dog”; } else if (i == 2) { animal = “cat”; } Some additional comments: I would recommend using Enum instead of String. This: for(int puzzleNum = 1; puzzleNum <= NUMANIMALS; mazeNum++) looks like an infinite loop to me, as your puzzleNum … Read more
[ad_1] Just about every angle-bracket language I know follows the following conventions: The condition of an if statement normally goes in parenthesis You shouldn’t have a curly brace at the end of turnCard(‘hit5′}; You shouldn’t have a ; at the end of your if-statements(or your for statement) Some languages allow you to use single-quotes like … Read more