The line: a[i] = strtok(s,” “); sets a[i] to a pointer within the string, which you’re modifying and which may eventually have the temporary NUL characters (from strtok) removed. You may want to try: a[i] = strdup (strtok (s,” “)); instead. Let me explain further. Say we have the command (as it exists in memory): … Read more
! returns the exit code of the process (0 in your case). If you need the output of the process you should use !! instead: val url = “https://morningconsult.com/alert/house-passes-employee-stock-options-bill-aimed-startups/” import sys.process._ val result = (“wget -qO- ” + url !!).toString println(“result : ” + result) (relevant documentation) solved Return value of process to String
Where is my mistake? There are possibly three mistakes. The first is that ‘variable_’ + ‘a’ obviously isn’t equal to ‘variable_1′. The second is the quoting in the argument to exec. Do for x in list: exec(“variable_%s=””” % x) to get variable_a etc. The third mistake is that you’re not using a list or dict … Read more
The page is not bogus. However, the code referenced per the link provided is actually Java, as the site refers to the ImageJ program, an “Image Processing and Analysis” Application. See here. solved In function main: undefined reference to exec [closed]
As I said in my answer to your previous question, you can fix this easily by using single quotes on the inside. PHP Code <?php $eff=40; $pos=34; $i = ‘hello’; $line=exec(“tail $i.dssp -n $eff | awk -F’ ‘ -v var=$pos ‘{if ($2==var) print FNR}'”); print “$line\n”; ?> Sample Input (hello.dssp): foobar 34 Sample Output: 1 … Read more