A watchdog is a mechanism that periodically tests whether a process or thread is running properly. If it’s not, it either restarts it or notifies an administrator, depending on the needs of the application. The details of how you implement this will depend on the application design. solved What is a watchdog? [closed]
Order is O(n^1.5). O(n) < O(n log n) < O(n^1.5) < O(n^2). So answer is 4. solved Analysis of algorithm and finding its time complexity
If I understand you correctly, you have a structure containing several members of different types and you are looking for a way how you could compare instances of this struct. It could look the following way: struct X { std::string s; char c; int i; bool operator==(const X& ref) { return s == ref.s && … Read more
You have multiple problems with your code. Variable names could be more informative l -> left_side. This way you don’t need to have a comment on every line. You use a variable n that is not initialized to anything. Perhaps split your code into multiple functions. Then you can investigate if each function does what … Read more
The sorting algorithm for Arrays.sort(int[] a) is a tuned quicksort. Ref: https://docs.oracle.com/javase/6/docs/api/java/util/Arrays.html#sort(int[]) Read this article: http://citeseerx.ist.psu.edu/viewdoc/download?doi=10.1.1.14.8162&rep=rep1&type=pdf for understanding the Quick-sort used in Array.sort() by JON L. BENTLEY & M. DOUGLAS McILROY In Java 7 pivot dual quick-sort algorithm is used for Arrays.sort(int[] a) i.e. refer this: What’s the difference of dual pivot quick sort and … Read more
In-place? Probably something like this: byte[] Reverse( byte[] b ) { for ( int i = 0 , int j = b.Length-1 ; i < j ; ++i, –j ) { arr[i] ^= arr[j] ; arr[j] ^= arr[i] ; arr[i] ^= arr[j] ; } return b; } Idempotent, where you allocate a new array to … Read more
I think you missed the most important one: algorithms. Understanding the complexity, know the situation to use them, why use them and more important, how to implement them. I’m pretty sure that you already know a lot about algorithms but if you think that your tool-knowledge (aka the programming languages) are good enough, you should … Read more
Use a hashMap and check if this key already exists then update the double value by adding existing double value then put in the map. public static void main(String[] args) { List<MyObject> list = new ArrayList<MyObject>(); list.add(new MyObject(“a”,”b”,”c”,new BigDecimal(10.23))); list.add(new MyObject(“a”,”b”,”e”,new BigDecimal(10.23))); list.add(new MyObject(“a”,”b”,”c”,new BigDecimal(10.23))); list.add(new MyObject(“a”,”b”,”d”,new BigDecimal(10.23))); Map<MyObject,MyObject> map = new HashMap<MyObject,MyObject>(){ @Override public … Read more
I found the answer i was looking for from below link. [http://hawkee.com/snippet/10086/] for anyone who is interested in this finding out i will post it here. There is second solution for this also using array within array. Which i will post below this, <?php class Matrix { public $arr, $rows, $cols; function Matrix($row, $col) { … Read more
I got requested result with below codes, another approach than what Marcos provided and I was able to find as well. Only additional thing is you need is to pad arrays to maximum length + 1 with numpy pad. def elementsum2array(arr1, arr2): ”’ 1. Make the arrays of same length padding at the beginning/left side … Read more
&c – Is the address of c. foo returns a pointer to this local variable – c. This is bad and should not be done – as c will be out of scope – hence its address will be invalid solved what does int* foo (int a) return in c++ [closed]
When you call CreateStack, the pointer is passed by value. The pointer that is returned by the call to malloc in your function is never assigned to the STACKHEAD. Try writing a CreateStack function that returns a pointer to the stack that gets created. It should not take any arguments. 1 solved Data Structre of … Read more
Suppose such a data structure existed. Then here is an O(n) comparison-based sorting algorithm: Push() every item into this data structure. Pop() them all off in sorted order. No O(n) comparison-based sorting algorithm can exist, therefore no such data structure can exist. solved How to design a data structure which supports the following operations in … Read more
Since your files are sorted, you don’t have to store them or even parse them outside of lines. You can keep advancing in the sequence with the lesser current element: def count_equal(a, b): “”” Counts the number of values that are equal in two sorted iterables. >>> odds = [1, 3, 5, 7, 9, 11, … Read more
change to at main struct link *head=NULL; char choice; create(value, &head); at create if(*head==NULL) // or if(temp==NULL) solved Compile fails for [Error] ld returned 1 exit status [closed]