[ad_1] Try stringOne .filter(function(el) { return el !== “”; }) .join(” – “); The filter gets rid of all elements that are empty, join should be straightforward. 1 [ad_2] solved Logically concatenating strings separated by hyphens
[ad_1] Just pass empty string to end parameter in print function after strippping off the newline character. print (line, end = “”) print by default print the content in a new line for each iteration but by passing empty string to the end parameter, this default behaviour won’t work. If you failed to remove the … Read more
[ad_1] I solved it!! Thank your comments and suggestions..I’ll improve the way I question.. HAHAH I hope you guys and gals get the logic. Quite simple 🙂 string group = “|17|11|05|”; string[] words = group.Split(‘|’); foreach (string word in words) { if (word.ToString() != “”) { string cg = word; } } 1 [ad_2] solved … Read more
[ad_1] You can use StringBuffer or StringBuilder for this task, StringBuilder would be my choice since its more efficient. its not thread safe so multiple threads can call its methods simultaneously. String reversedString = new StringBuilder(originalString).reverse().toString() If you prefer not to use API support you can do something like this static String reverse(String stringIn) { … Read more
[ad_1] The most simple approach would be to just check for every element in src vector, if an duplicate exists in dest vector or not. If it exists just append Duplicate to it, else you can just push back the element as a new element in dest vector. The follow code would do the job … Read more
[ad_1] First of all, your ternary operator seems to be quite repetetive. There is a way to make it shorter: totalPrice = salesPrice + ( salesPrice <= 25 ? minShipping : maxShipping ); Then, it is a good habit to declare your variables before you use them using var keyword. In this particular case the … Read more
[ad_1] You have to get the first letter of the first name, and make sure that it is capital; first.toUpperCase().split()[0] outputs the first letter and ensures that it is capital. function printName(first, last) { var fullName = last + “,” + first.toUpperCase().split()[0] + “.”; // “,” should be “, ” ; with a space return … Read more
[ad_1] OK. Let’s generalize the problem (see comments for the question): let us join all the properties which are: public and not static. Readable and Writable. Not indexers (what should we do with this[int, int] property?). Of specified types (e.g. string, int, decimal, double) only (how can we save, a property of, say, IComparer<int> type?). … Read more
[ad_1] This should do the trick: <li><?php echo $book . ” (” . $isbn . “)”; ?></li> 0 [ad_2] solved How to concatenate a space in php
[ad_1] It would help if you provided more information. Here is an example: df <- data.frame(x=1:26, y=as.factor(LETTERS)) paste(df$x, df$y) [1] “1 A” “2 B” “3 C” “4 D” “5 E”… paste(df$x, df$y, sep=””) [1] “1A” “2B” “3C” “4D” “5E”… It doesn’t matter what class the elements are, the engine will convert them to character class. … Read more
[ad_1] You can use concat as SELECT Source, QtyPrevious, QtyToday, ProductPrevious, ProductToday, AvaDatePr, AvaDateToday, Clusters, CONCAT(X, ”, Y) as Z from your_table_name; [ad_2] solved How to concatenate two different values from two different columns with comma ” , ” using TSQL?
[ad_1] You need to add a + before each value you add, so a + after raza (not just before), peso and so on. Thats how string concatenation works in Java. Like this: System.out.println (“El Peso de la” + raza + “es de ” + peso + “kg y se alimenta de ” + alimeto); … Read more
[ad_1] You use: SELECT Tablename, CONCAT(fieldName1,’, ‘,fieldName2,’, ‘,fieldName3) AS name FROM Tablename; 1 [ad_2] solved Simple SQL concatenation
[ad_1] I think the recommended answer would be something along these lines: hello=”Hello” world=’World’ hello_world=hello + ‘ ‘ + world print=hello_world Run output: Hello World [ad_2] solved What’s wrong here? (concatenation) in Python
[ad_1] Try the below code, it assumes you have headers and that unique ID is in column A and description in column B. Option Explicit Sub HTH() Dim vData As Variant Dim lLoop As Long Dim strID As String, strDesc As String ‘// Original data sheet, change codename to suit vData = Sheet1.UsedRange.Value With CreateObject(“Scripting.Dictionary”) … Read more