Some notes that can be used to speed things up: Rotating by K, when K>N, is equivalent to rotating by K%N (as each rotation of N is an expensive no-op). You don’t actually need to generate the rotated array; you just need to print the values as they would appear in the rotated array. In … Read more
A little help. C | JS —————–|—————— int x; | var x; —————–|—————— int xs[n]; | var xs = []; —————–|—————— printf(…) | console.log(…) —————–|—————— int f (int x) { | function f (x) { … | … return y; | return y; } | } The remaining syntax from your post is almost identical … Read more
The logic of your for loop must be modifies to get an equilateral triangle. The below code works, The outer most for loop I have used is to print the numbers in a new line every time after completing the inner loops the outer loop prints a new line. The first inner loop isto print … Read more
This is useful—it does the same thing as DateTime.Parse, BUT DOES NOT THROW ANY EXCEPTIONS It returns true if the parse succeeded, and false otherwise. protected void Foo() { // Use DateTime.TryParse when input is valid. string input = “2014-02-02T04:00:00″;//”2014-02-02”; DateTime dateTime; if (DateTime.TryParse(input, out dateTime)) { lblresult.Text = dateTime.ToString(); } else { lblresult.Text = … Read more
You can do it this way: var result= xdoc.Descendants(“image”) .Where(x => x.Attribute(“size”).Value == “large”) .Select(x => new User{ Image = x.Value }); Here is Working Example Fiddle solved LINQ to XML attributes
I defined my checksum variable as unsigned long int because that was typedefed as a uint4 in the library I am porting (where the basis for this code comes from). Turns out that the library was only used on 32 bit architectures, so an unsigned long int is 4 bytes whereas on my machine (64 … Read more
Just add the following code to the bottom. \x03 is hexadecimal code for the heart character on a US Windows console, which I assume you are using: printf(“\x03 \x03\n”); printf(“\x03\x03 \x03\x03\n”); printf(“\x03 \x03 \x03 \x03\n”); printf(“\x03 \x03 \x03 \x03\n”); printf(“\x03 \x03 \x03\n”); printf(“\x03 \x03\n”); printf(“\x03 \x03\n”); Output of the whole program: ♥♥♥♥♥♥♥♥♥ ♥ ♥ ♥♥♥♥♥♥♥♥♥ … Read more
In my experience, DIV’s are not registered to the server like ASP controls are so calling them directly would produce bad results. When making changes to the controls, i.e. adding styles, make sure you tell ASP what kind of control you have. For example: HtmlGenericControl _fail = (HtmlGenericControl)Page.FindControl(“fail”); _fail.Style.Item(“visibility”) = “hidden”; Edit: The problem lies … Read more
The problem is in the definition of your main function. You need to add a parameter list. Either of these are valid: int main() { …. } int main(int argc, char** argv) { … } solved ‘No suitable conversion function’ with cout [closed]
There are many problems here z is a local variable int. its address will not be useful to return, because it will be out of scope. returning an offset from its address is even worse, since that is a totally unrelated place in memory. you also have an off-by-one error. imagine Number elements is one. … Read more
DataContractSerializer serializer = new DataContractSerializer(typeof(List<Dictionary<String, String>>)); byte[] byteArr; using (var ms = new System.IO.MemoryStream()) { serializer.WriteObject(ms, stringlist); byteArr = ms.ToArray(); } return byteArr; solved How to convert any type of Object into byte array in Windows phone 8?
std::vector::insert accepts a const reference to value type, which can only be assigned to other const references. Your operator=, though, accepts a non-const reference, so it cannot be used in overload resolution. General solution: Make operator= accept a const reference. Specific solution for your case: Just drop your custom operator= entirely! There are no types … Read more
You need to check oras like this string doc = @”<Absolventi nume=”Ace Timisoara”> <id>7</id> <oras>Timisoara</oras> </Absolventi>”; XmlDocument xDoc = new XmlDocument(); xDoc.LoadXml(doc); foreach (XmlNode node in xDoc.ChildNodes) { Console.WriteLine(node.Attributes[“nume”].Value); Console.WriteLine(node[“id”].InnerText); Console.WriteLine(node[“oras”].InnerText); } Test here 1 solved Xml Parsing in Visual Studio 2015
Well you must have a foreign key for the parent. Here is an example select * from person parent left join person child on child.Parent_ID = parent.ID where parent.Name like ‘Adam’ I think this should work for you, you could also left join the sub children of the sub children. Or you can write query … Read more
in this code snipped you declared a function with an argument passed to it by value: void increment(int value) { value++; } What it really does, it increments this value … inside the function, and that is it. It does not return the value nor updates any other variable. There are several ways you can … Read more