[ad_1] Well, first, this is not the way to get the path to the desktop directory. Instead, just do this: Environment.GetFolderPath(Environment.SpecialFolder.DesktopDirectory) Unlike your solution, this will work with folder redirection, remote profiles, as well as with future (and past!) Windows versions. Not to mention that Environment.Username isn’t necessarily the correct folder name anyway 🙂 Second, … Read more
[ad_1] Figured it out. I was being an idiot and not escaping the ‘\’ before the v11.0. Thanks all! openCon = new SqlConnection(“Data Source=(LocalDB)\\v11.0;” + “AttachDbFilename=” + AppDomain.CurrentDomain.BaseDirectory + “Encounter.mdf;” + “Integrated Security=True”); [ad_2] solved How to connect to SQL Server database file in my solution [closed]
[ad_1] I am unsure what problems you are having exactly but I can see the following errors in the code: In the initialise_list() function the for loop will be iterating too many times and going beyond the bounds the of array: for(int i = 0; i < sizeof(list); i++) { as sizeof(list) will return the … Read more
[ad_1] void setvalores(int vi, int fu, int ve) { velocidad = &ve; vida = &vi; fuerza = &fu; }; The pointers to vi, fu, and ve get invalidated when the function returns. You’re not seeing addresses being printed, but simply garbage. Your entire design doesn’t and shouldn’t need to use pointers though. 8 [ad_2] solved … Read more
[ad_1] As I said in the comments, you could embed it in a while loop bool continue = true; while (continue) { Console.WriteLine(“Enter Customer Details (s)”); Console.WriteLine(“Enter usage data (u)”); Console.WriteLine(“Display usage data (d)”); Console.WriteLine(“Exit (e)”); string menu = Console.ReadLine(); switch (menu) { case “s”: //statement break; case “u”: //statement break; case “d”: //statement break; … Read more
[ad_1] listenfd = lacz_tcp(wiadomosc->port); From what I can tell, the port has not been initialized before you call bind. Log the port to be sure that the server is listening on the correct port. 2 [ad_2] solved Connection refused – tcp socket in linux [closed]
[ad_1] For many compilers, these will be identical. (Note that I said many compilers – see my disclaimer below). For example, for the following C++ code, both Test 1 and Test 2 will result in the same assembly language: int main() { int test = 0; // Test 1 test++; // Test 2 test += … Read more
[ad_1] ok, calling main is not a good idea, but I guess the question is more about how having 2 functions calling each other. you need to forward declare at least one: int write(); //forward declare int read() { return write(); // use write which is still forward declared for now } int write() { … Read more
[ad_1] So, you want to sort an array of custom objects, like this: typedef struct { char c; // a character int i; // a number } pair; Then you can apply a standard function qsort() with a custom compare function like this: int compare(const void *a, const void *b) { pair *p1 = (pair*) … Read more
[ad_1] Serializing a List<LinkedListNode<string>> is a bit of an odd thing to do – normally one would just serialize the underlying linked list. Perhaps you’re trying to serialize a table that gives the nodes in a different order than the underlying list? If that’s the case, it might appear that one could serialize the node … Read more
[ad_1] Try the following approach #include <stdio.h> #include <string.h> int main(void) { enum Animal { cat, dog, elephant }; char * animal_name[] = { “cat”, “dog”, “elephant” }; enum Animal b; size_t n; char s[100]; fgets( s , sizeof( s ), stdin ); n = strlen( s ); if ( s[n – 1] == ‘\n’ … Read more
[ad_1] Yes, you can simply use multiple from clauses: var result = from x in list1 from y in list2 from z in list3 select x+y+z; In the csharp interactive shell, this gives: csharp> var list1 = new string[] {“A”, “B”, “C”}; csharp> var list2 = new string[] {“1”, “2”, “3”}; csharp> var list3 = … Read more
[ad_1] Well, if I am interpreting your question right, you can declare an array or list, then initialize these elements in a loop For example (array) (if you want a fix number of elements): int n = 10; // number of strings string[] str = new string[n]; // creates a string array of n elements … Read more
[ad_1] char y[] = { ‘a’, ‘b’, ‘a’, ‘c’ }; int count[52] = {0}; for (int i = 0; i < (sizeof(x) / sizeof(char)); i++) { if (y[i] >= 65 && y[i] <= 90) count[y[i] – ‘A’]++; else if (y[i] >= 97 && y[i] <= 122) count[(y[i] – ‘a’) + 26]++; } for (int i … Read more
[ad_1] The memory is being managed by your numpy arrays. As soon as they go out of scope (most likely at the end of the PySparse constructor) the arrays cease to exist, and all your pointers are invalid. This applies to both large and small arrays, but presumably you just get lucky with small arrays. … Read more