[Solved] Setting width in C# ActiveForm has no effect
[ad_1] From what you’ve said, and assuming that the code is running from Form1: int width = this.Width; int height = this.Height; [ad_2] solved Setting width in C# ActiveForm has no effect
[ad_1] From what you’ve said, and assuming that the code is running from Form1: int width = this.Width; int height = this.Height; [ad_2] solved Setting width in C# ActiveForm has no effect
[ad_1] Writing into the heap beyond a valid malloc’ed location results in undefined behavior. It may or may not result in a seg fault. Depends on what is in the heap location and how it is used by the rest of the program. Your program may not fail at all. But it does corrupt the … Read more
[ad_1] Your Handle’s copy c-tor is invalid. It should be like this: Handle(const Handle<T>& other) : baseItem(other.baseItem), refCount(other.refCount) { ++*refCount; } http://ideone.com/DB7L9p [ad_2] solved The handle class in C++ [closed]
[ad_1] The first error can help you search for “C# methods”, which will lead you to this: Methods are declared in a class or struct by specifying the access level such as public or private, optional modifiers such as abstract or sealed, the return value, the name of the method, and any method parameters. These … Read more
[ad_1] The problem is indeed here. char instring[2]; Now let’s think about this line. gets(instring); Let’s say you type 10 and hit enter. What will go into instring is three bytes. 1 0 A terminating null. instring can only hold two bytes, but gets will shove (at least) three in anyway. That extra byte will … Read more
[ad_1] You probably need to turn on warnings in your compiler. The function f returns a bool (not an int as declared) and does not do so unless the number of divisors of x is equal to two. This are fairly trivial mistakes that any decent C++ compiler should warn you about. Do not ignore … Read more
[ad_1] Remarks: You do not free allocated memory by using delete[]. That’s a very bad practice. You always should remember to free memory you allocated. It is very, very uncomfortable to choose jagged arrays (arrays of arrays) for long term use. A lot easier solution is to allocate a single array: double * phi = … Read more
[ad_1] There are two separate errors. First, you forgot to add main.cpp to your makefile. Second, your main.cpp doesn’t contain a global function named main. A class member function named main doesn’t qualify. You need a function named main in the global namespace with external linkage. [ad_2] solved Makefile issue (Undefined symbols for architecture x86_64: … Read more
[ad_1] Your are passing the array, not its address. arr is an int[][] array (in fact it is pretty the same as &(arr[0]), which is a pointer to (the address of) the first line of your array. In C, there is no practical difference between an array and the corresponding pointer, except you take it’s … Read more
[ad_1] Here is solution using Xml Linq.. Why is there two nested levels of navPoint? : using System; using System.Collections.Generic; using System.Linq; using System.Text; using System.Xml; using System.Xml.Linq; namespace ConsoleApplication110 { class Program { const string INPUT_FILENAME = @”c:\temp\test.xml”; const string OUTPUT_FILENAME = @”c:\temp\test1.xml”; static void Main(string[] args) { XDocument doc = XDocument.Load(INPUT_FILENAME); XElement root … Read more
[ad_1] This line: result = n! / ((n-k)!*k!); …is not valid C code. ! in C means “not”. You will need to provide a factorial function so that you can call: result = factorial(n) / (factorial(n-k) * factorial(k)); [ad_2] solved Combination formula “n! / ((n-k)!*k!)” doesn’t work [closed]
[ad_1] This example allows the user to enter numbers “indefinitely” without the need for prompting how many to enter. Of course, your computer only has so much RAM, so there is a limit, but not a practical limit. Essentially, you need to choose an initial size, then allocate more space dynamically when that size is … Read more
[ad_1] You have two problems with that code: The first is that ‘add’ is a multi-character literal, and not a string. A string would use double-quotes like “add”. The second problem is that you can’t use equality comparison to compare string, as that will compare the pointers and not the contents of the strings. To … Read more
[ad_1] There is the String.Join-method designed for this. var mystring = String.Join(” OR “, idsArr); This will result in the following string: export_sdf_id=3746 OR export_sdf_id=3806 OR export_sdf_id=23 OR export_sdf_id=6458 OR export_sdf_id=3740 OR export_sdf_id=3739 OR export_sdf_id=3742 Note that the brackets are omited as they are not needed for your query. 1 [ad_2] solved How to create … Read more
[ad_1] You could use a simple character array: static const char symbols[] = {‘@’, ‘#’, ‘^’, ‘*’}; char c; std::cin >> c; unsigned int value; for (value = 0; value < sizeof(symbols); ++value) { if (c == symbols[value]) { break; } } if (value >= sizeof(symbols)) { // Symbol not found. } else { value … Read more