This should do the trick: #!/bin/bash INPUT=”$@” SIZE=${#INPUT} for ((i=0; i < ${SIZE}; i++)); do echo “${INPUT}” INPUT=”${INPUT:0:${i}} ${INPUT:$((i+1)):${SIZE}}” #INPUT=”$(echo “$INPUT” | sed “s/^\(.\{${i}\}\)./\1 /”)” done I added a sed option in the comment, although it creates a sub-process when you don’t really have to. 0 solved Linux ‘cut’ command line and replace
This is a bash script, not a Python script. Run it using ./script_name.sh or bash script_name.sh instead of python script_name.sh. 1 solved Why doesn’t Python run my bash code?
#!/bin/bash cat datafile| \ while read line do lastword=${line##*,} echo $lastword echo $line > $lastword done 3 solved How to read a file line by line and making a new file for each line having same filename as last word of each line? [closed]
In POSIX grep, -v is a matching control option to invert match. In this usage case, it is telling grep to match all lines that do NOT contain the string “:0” For more information, man grep 1 solved how does the bash command “grep -v “:0″” work
You have two bits here. One is to schedule a cron job and the other is to get the file & save it. Steps : Open the terminal & run crontab -e minute(0-59) hour(0-23) day(1-31) month(1-12) weekday(0-6) command In place of minute, hour, day, month & weekday. Also provide the command to run. The command … Read more
with sed based on position $ echo abc-def-ghi-2017-10-31 | sed ‘s/-/./4g’ abc-def-ghi-2017.10.31 based on surrounding chars $ echo abc-def-ghi-2017-10-31 | sed -r ‘s/([0-9])-([0-9])/\1.\2/g’ abc-def-ghi-2017.10.31 based on the position from the end of string $ echo abc-def-ghi-2017-10-31 | rev | sed ‘s/-/:/g; s/:/-/3g’ | rev abc-def-ghi-2017:10:31 2 solved sed/regex to change only few of multiple matching … Read more
This might work for you (GNU sed): sed -r ‘s/^(.*\|.*\|)([^,]*),([^|]*)(\|.*\|.*\|)([^,]*),([^|]*)(.*)/\1\2\4\5\7\n\1\3\4\6\7/;P;D’ file Iteratively split the current line into pieces, building two lines separated by a newline. The first line contains the head of the 3rd and 6th fields, the second line contain the tails of the 3rd and 6th lines. Print then delete the first of … Read more
Put function cd() { test $# -eq 0 && return 0 if [ `basename $1` == “go” ]; then builtin cd “$1/src” else builtin cd “$@” fi } in your ~/.bashrc. Note that you won’t be able to use command-line options when cd-ing into your Go directory because ideally we’d process only the last argument … Read more
-r is to reverse the results -n specifies numerical ordering -k5 indicates it is comparing the entries in the 5th column solved Can anyone tell me what this expression denotes for bash sorting “sort -r -n -k5”
import os from shutil import move from time import time def mins_since_mod(fname): “””Return time from last modification in minutes””” return (time() – os.path.getmtime(fname)) / 60 PARENT_DIR = ‘/some/directory’ MOVE_DIR = ‘/where/to/move’ # Loop over files in PARENT_DIR for fname in os.listdir(PARENT_DIR): # If the file is a directory and was modified in last 15 minutes … Read more
I suggest: while read -r c1 c2 c3; do curl –data “field1=$c1&field2=$c2&field3=$c3” http://webserver/resource.asp done < file.csv solved BASH – read lines and fetch column values using curl
The way to do this is by using awk as you already suggested. As you say, you want to print the lines starting from the first occurrence where you have 3 fields, this can easily be done by setting a print flag (let’s call it p)’ awk ‘(NF==3){p=1};p’ file This will print everything starting from … Read more
You can change the date of the mac using the following command from the terminal. date -u {month}{day}{hour}{minute}{year} Replaced bracket with a two digit number. To set, October 16th 2020 21:16 would become the following command: date 1016211620 Or you can create apple script to do it: set ntpdPID to do shell script “systemsetup -getusingnetworktime; … Read more
You can try this: #!/bin/bash while read -r line; do date=”${line:4:8}” echo “$line” >> “${date}.txt” done < filenames.txt 0 solved Creating text files based on list of file names [closed]
You can use the following sed command, let me know if you need additional explanations about it: sed -E -i.bak ‘s/^([^\s]*)\s+([^,]*),[^,]*,\s*([^\s]*)\s+([^\s]*)\s*$/\4:\2:\1:\3/g’ test_add_file.in; TESTED on: In a nutshell, you are define a regex that sed will use to look in your text file to fetch the required patterns, then you use backreferences to reuse the actual … Read more