[ad_1] Below is a worked solution: let arr = [ { keep1: ‘abc’, keep2: ‘def’, buh1: false, buh2: false }, { keep3: ‘abc’, keep4: ‘def’, buh3: false, buh4: true }, { keep5: ‘abc’, keep6: ‘def’, buh5: false, buh5: false } ] let whiteList = [‘keep1’, ‘keep2’, ‘keep3’, ‘keep4’, ‘keep5’]; arr.forEach(function (obj) { Object.keys(obj).forEach(function(key) { if … Read more
[ad_1] It’s because your product starts at 1. If it started at zero, the product would be three. Assuming that only the second loop is running. If the first loop is running as well, then I would expect the result to be 5. Since product = 2 after the first loop, then 0 + 1 … Read more
[ad_1] public void isSpace(String[] array) { for (int i=0; i<array.length; i++) { if( (array[i] == null) || (array[i].trim().length() == 0)) { //true on null, empty string, or white space only. Do something here array[i] = “add some thing here”; } else { //not null, not empty string, or not white space. Do something here } … Read more
[ad_1] You can fetch the ids and classes of each tr entry in your table by using the following function: /* The function that fetches the data. */ function fetchData() { var /* Create an object to store the data. */ data = {}, /* Get every ‘tr’ element of the ‘tbody’. */ elements = … Read more
[ad_1] Let’s say I have an array of characters (a string ) and I want to count how many time each character appears. However there should be no if [ad_2] solved Let’s say I have an array of characters (a string ) and I want to count how many time each character appears. However there … Read more
[ad_1] private ArrayList<Student> readFile() throws FileNotFoundException { String fName = “p02-students.txt”; Scanner scan = new Scanner(new File(fName)); ArrayList<Student> studentList = new ArrayList<Student>(); while (scan.hasNext()) { String studentType = scan.next(); if (studentType.equals(“C”)) { studentList.add(readOnCampusStudent(scan)); } else { studentList.add(readOnlineStudent(scan)); } scan.nextLine(); } scan.close(); return studentList; } I didn’t get the error you mentioned earlier, but I was … Read more
[ad_1] You need to initialize marks array. int[] Math = {85,65,40,20}; int[] English = {35,55,68,75}; int[] ICT = {50,35,69,95}; int i; int x=1; int[] marks = new int[4]; if (x==1) { marks=Math; } else if (x==2) { marks=English; } else if (x==3) { marks=ICT; } for (i=0; i<4; i++ ) { System.out.print(marks[i] + ” “); … Read more
[ad_1] You can use this method **Array.prototype.shift()** It removes the first element from an array and returns that element. [ad_2] solved How to remove the first element from an array? [closed]
[ad_1] The characters you are trying to print aren’t visible characters. You can check what visible ones (starting from 33) at ASCII table 1 [ad_2] solved Cant put a number into 2d array idk why [closed]
[ad_1] //Initiate new array to store coords $latlongs = array(); //Loop through your array foreach($yourArray as $k=>$v){ // Loop through the partnerlist to extract lat/lon // Append to your coord array, and preserve the industry key // So that you know which lat/lons came from where foreach($v[‘partnerlist’] as $a){ $latlongs[$k][] = array(“latitude”=>$a[‘latitude’],”longitude”=>$a[‘longitude’]; } } This … Read more
[ad_1] You have a 2D array. The usual way to traverse it, is be double for loop. The usual order will be this: 1st row – 1st column 1st row – 2nd column .. 1st row – last column 2nd row – 1st column … last row – last column Assume you are using the … Read more
[ad_1] Here is a typical example of pulling 50 columns of data with a variable number of rows from the active worksheet into a two dimensional array: Sub GetData() Dim r As Range Dim N As Long N = Cells(Rows.Count, “A”).End(xlUp).Row arr = Range(“A4:AX” & N) End Sub [ad_2] solved Read worksheet into 2 dimentional … Read more
[ad_1] var result = string.trim().split(“, “).map(el=>el.split(“|”).map(n=>+n)) this splits the string into an array of these groups ( yet as string ) “1|2, 3|4” => [“1|2″,”3|4”] then maps this array to a new array containing the strings splitted and converted to numbers: => [[1,2],[3,4]] 2 [ad_2] solved Convert string into several integer arrays [duplicate]
[ad_1] Try this int indexModifier = 0; for (int i = 0; i < Math.sqrt(second.Length); ++i) { for (int j = 0; j < Math.sqrt(second.Length); ++j) { second[j + indexModifier, j] = first[i + indexModifier); } ++indexModifier; } 1 [ad_2] solved One Dimensional Array to Multidimensional Array
[ad_1] What about this, you iterate over the array and check that the square of the square root is the same as the original number. If so, you add it to a list that you convert to an array once you are done. int[] numbers = new int[] { 1,2,3,4,5,6,7,8,9,10 }; List<Integer> resultList = new … Read more