<?php $arr = array(); //your array, your values. $arrGonnaBe = array(); foreach($arr as $a){ $exp = explode(“##”,$a); if(count($exp)>1){ foreach($exp as $e){ array_push($arrGonnaBe,$e); } }else{ array_push($arrGonnaBe,$exp[0]); } } print_r($arrGonneBe); ?> 0 solved make new array from existing array based on a delimiter in php
As you mentioned the split-function can handle this. String[] types = new String[columnNameType.length]; String[] names = new String[columnNameType.length]; for(int i = 0 ; i< columnNameType.length; ++i){ names[i] = columnNameType[i].split(” “)[0]; types[i] = columnNameType[i].split(” “)[1]; } iterate your array and split every element on its own. 1 solved How to split an string array element by … Read more
behold, LINQ // don’t need to know which is start or end, assuming string compare works as expected. var addresses = new List<string>() { “192.168.10.10”, “192.168.10.20” }; // convert string to a 32 bit int Func<string, int> IpToInt = s => { return ( // declare a working object new List<List<int>>() { // chop the … Read more
Jim’s answer would be the right way to go unless for any reason you can’t modify that code, otherwise: $.each(Analytic_Event, function(key, item) { // do whatever with item }); if you really have to anyways 1 solved Javascript: Can’t get an on-click event to search through an array
ArrayList’s in Java are complex data structures based on object oriented programming, while arrays in C programming language are simply indexed chains of allocated memory of certain lengths. The only way to access an element in C programming language array is to give it’s index, which is used to compute the address of variable in … Read more
string value = Interaction.InputBox(“Enter Array size”, “Enter Array size”); int array = 0; if (int.TryParse(value, out array)) { int[] size = new int[array]; txtOutput.Text = “Numbers: ” + “\r\n”; for (int i = 0; i < size.Length; i++) { string prompt = Interaction.InputBox(“Enter values” + (i + 1), “Enter values”); int num = 0; if … Read more
I’ve knocked up a quick program to test how long it takes, here I believe I have used a 20 digit long number. I know it’s not exactly the parameters that you have asked for, however it gives a good illustration to what kind of speed you can be expecting. This was run on a … Read more
May be you want this. #include<iostream> using namespace std; int main() { const int m = 8; int i, k; int A[m] = { 1,2,3,4,5,6,7,8 }; int B[m]; k = 0; for (i = 0; i < m; i++) { if (A[i] % 2 == 0) { B[k] = A[i]; k = k + 1; … Read more
You already import java.util.Arrays why not use that to print out the sequence? Note: I removed the unnecessary import of java.util.Random (you can use revert back to using that if you want, and whatever num was for as I think that made everything more complicated than required. import java.util.Arrays; public class problem1 { public static … Read more
In-place? Probably something like this: byte[] Reverse( byte[] b ) { for ( int i = 0 , int j = b.Length-1 ; i < j ; ++i, –j ) { arr[i] ^= arr[j] ; arr[j] ^= arr[i] ; arr[i] ^= arr[j] ; } return b; } Idempotent, where you allocate a new array to … Read more
One method is to convert array into object, and use productId as key: const data = [ { productId: 6, productName: “pouch”, productPrice: 29000, discountRate: 19, optionName: “13inch”, optionPrice: 0, qty: 2, }, { productId: 6, productName: “pouch”, productPrice: 29000, discountRate: 19, optionName: “15inch”, optionPrice: 1000, qty: 1, }, { productId: 4, productName: “pouch”, productPrice: … Read more
You can do this with a list comprehension. For example: mylist = [[0.0,0.0,0.1], [0.4,0.23,0.175], [0.0,1.,0.5], [0.0,0.03,0.1], [0.02,0.0,0.3]] indices = [0,2,3] result = [mylist[i] for i in indices] result is now [[0.0, 0.0, 0.1], [0.0, 1.0, 0.5], [0.0, 0.03, 0.1]] 2 solved Get an item from a list if its index is on another list
The reason is that a jagged array is actually an array of arrays of values. Since arrays are objects, reference types, it means that if you construct a jagged array with room for 10 arrays, all those array references are initialized to null. In other words: int[][] a = new int[10][]; a[0][0] = 10; throws … Read more
You want a variable lenght array, you can do it like this: int digit; scanf(“%d”, &digit); char test [digit+1]; This will work for your purposes. Usual restrictions of course apply. Keep in mind this functionality was only added in the C99 Standard. So if your compiler supports only previous standards, this will not work. However, … Read more
import java.lang.reflect.Array; public class freq { public static void main(String[] args) { double a[] = { 0.0855, 0.0160, 0.0316, 0.0387, 0.1210, 0.0218, 0.0209, 0.0496, 0.0733, 0.0022, 0.0081, 0.0421, 0.0253, 0.0717, 0.0747, 0.0207, 0.0010, 0.0633, 0.0673, 0.0894, 0.0268, 0.0106, 0.0183, 0.0019, 0.0172, 0.0011 }; System.out.println(“c = ” + a[2]); } } 1 solved How to print … Read more