[ad_1] argv stands for argument value and it represents the arguments passed to your program when it is launched from the command line. For example, if your program is called example.py, and you run it like this: $ example.py ‘hello’ Then argv is hello. raw_input is a way to prompt the user for some input. … Read more
[ad_1] You haven’t actually provided code that exhibits your problem but, to answer your question, ways to pass argv[2] as a string to a function include #include <cstring> #include <iostream> void func(const char *s) { // treat s as a zero terminated string if (std::strcmp(s, “Hello”) == 0) { std::cout << “You said hello\n”; } … Read more
[ad_1] [Note: C does not have builtin string type. What C has is character array] This is a very easy to solve problem. Here’s the code given, it uses stdlib‘s builtin atoi function to convert string to int: #include <stdio.h> #include <stdlib.h> int main(int argc, char *argv[]) { if (argc == 2) { char *var_str … Read more
[ad_1] Try something in the spirit of: program.exe textCopy “C:\path to\the source file\my source file.ext” “C:\path to\the destination file\my destination file.ext” It’s the double quotes around the file path in the command line you’re missing. 2 [ad_2] solved C: How to open a file using the parameter to main argv? [closed]
[ad_1] You can run the program as: IFS=$’\n’ ./sort.exe $(cat file.txt) Each line of the file will then be an argument to the program (setting IFS to just newline prevents spaces in the file from being argument delimiters). Then the program can loop over argv (except for argv[0], which contains the program name) to get … Read more
[ad_1] Quoting shamelessly from the C11 spec, chapter §5.1.2.2.1, (emphasis mine) — The value of argc shall be non-negative. — argv[argc] shall be a null pointer. — If the value of argc is greater than zero, the array members argv[0]through argv[argc-1] inclusive shall contain pointers to strings, which are given implementation-defined values by the host … Read more