Your problem is the last for loop. Each row will get the state of the last checked[] array entry. You should see that if you change the value of the last one. PS: Your code is a bit “messy” and can be optimized: @Override public View getView(final int position, View convertView, ViewGroup parent) { View … Read more
I have downloaded the stable version of Android Studio 2.0, it’s just an archive with files. Just unpack the archive wherever you want or download stable version with installer as listed in the table on the bottom of official page: https://developer.android.com/sdk/index.html solved How to install the new Android Studio 2.0
From the docs: When an application is launched, the system creates a thread of execution for the application, called “main.” This thread is very important because it is in charge of dispatching events to the appropriate user interface widgets, including drawing events. In other words, ALL UI-related tasks occur on the same thread, and it … Read more
may be you are trying to say that when you close the app user don’t have to enter the login credentials again ,what you say is auto login, for this. use shared preferences and session manager in android steps:- in your login page do check this following condition session = new SessionManager(getApplicationContext()); // Check if … Read more
Add this dependencies in build.gradle file compile ‘com.github.rey5137:material:1.2.2’ In Xml write this code. <com.rey.material.widget.Spinner android:id=”@+id/spinner_label” style=”@style/LightSpinner” android:layout_width=”match_parent” android:layout_height=”wrap_content” android:gravity=”center” android:minWidth=”128dp” android:padding=”8dp” app:spn_label=”Spinner with arrow” /> In Java class write this code. Spinner spn_label = (Spinner) findViewById(R.id.spinner_label); String[] items = new String[20]; for (int i = 0; i < items.length; i++) { items[i] = “Item ” … Read more
The instructions in the blog post are incorrect, in at least one area. The following paragraph from Step #3: The project will not currently build. We need to add the core.jar file (that we produced in the previous step) into our project. Right-click on ZXing project –> properties –> Java Build Path –> Add External … Read more
try to set listener on your exit Button ( in my example is : btn_exit ) your app will exit at all 🙂 public class testprj extends Activity { /** Called when the activity is first created. */ @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); Button btn_exit = (Button) findViewById(R.id.btn1); btn_exit .setOnClickListener(new OnClickListener() { … Read more
For doing some Action on Button Click following these Steps : STEP 1: Add a button in your Activity layout as: <Button android:id=”@+id/button_id_here” android:layout_width=”wrap_content” android:layout_height=”wrap_content”/> STEP 2: Add your NextActivity in AndroidManifest.xml as: <!– your other xml –> <application <!– your other xml –> <activity android:name=”.NextActivity” /> </application> STEP 3: In MainActivity code add a … Read more
java.lang.NullPointerException at android.widget.ArrayAdapter.createViewFromResource(ArrayAdapter.java:394) ArrayAdapter<Comment> adapter = new ArrayAdapter<Comment>(this, android.R.layout.simple_list_item_1, values); values has at least one null object in it, which you cannot have. You can read through the source code and see this happens here: T item = getItem(position); if (item instanceof CharSequence) { text.setText((CharSequence)item); } else { text.setText(item.toString()); // Line 394, when item is … Read more
If the EditText has no contents, it will return a blank string, or a “” In order to return with 0, simply set up an if statement: EditText editText = (EditText) mParent.findViewById(Rid_something); String string = editText.getText().toString().trim(); if (string.equals(“”)) { return “0”; } else { return string; } This will return 0 if blank, or the … Read more
iOS development must be done under OS X. The proper way to do this is to buy Mac hardware. You can build a Hackintosh if you’d rather, but you cannot install OS X in a virtual machine. What you could do, if you want to target multiple platforms (Windows Phone, iOS, Android) is to use … Read more
As the comments have stated, this is basically an unnecessary way to approach this. The Android platform automatically sends out Intents for certain changes, and Wifi status is one of them. You need only have a BroadcastReceiver registered that filters on that Intent to be able to respond to it. 2 solved How to broadcast … Read more
It is not a good practice to do so. If each app uses the same source code but different ressources, you should offer customization options within the main app. You won’t have good dev feedbacks by polluting the market this way. With customizations, you can reach as much users as you would with a 1000 … Read more
Usually when submit your App to Google Play you get an option to translate, I’m not sure on the working, but the other alternative is to translate all the text yourself and use separate values.xml for each lang. EDIT: Mygengo Translation APIMicrosoft Translator APIsSpeaklite Translate APIWebServiceX Translate API 8 solved how to translate text without … Read more
You can find the official documentation here To implement an AlertDialog you need to use the AlertDialog.Builder class too setup the AlertDialog. Then you can use the .create() method to create the AlertDialog, and then finally .show() of AlertDialog class to show the dialog. val alertDialog: AlertDialog? = activity?.let { val builder = AlertDialog.Builder(it) builder.apply … Read more