Here in above image of structure of your JSON you should better use http://jsonviewer.stack.hu/ and paste your json here to view and understand its structure and then can use GSON or any other library to parse it and get what you want out of it 2 solved How to parse this? [closed]
Do this : @Override public boolean onTouch(final View view, MotionEvent event) { final int action = event.getAction(); int x = event.getX() // or getRawX(); int y = event.getY(); switch(action){ case MotionEvent.ACTION_DOWN: if (x >= xOfYourBitmap && x < (xOfYourBitmap +yourBitmap.getWidth()) && y >= yOfYourBitmap && y < (yOfYourBitmap + yourBitmap.getHeight())) { //You’ve pressed on your … Read more
Depends on the website. For instance a website that allows the developer to get a XML responds, as a result of the search request. You can then easily parse the XML and feed it to your app. 1 solved website specific search within an android app
When you have an error on your response, your response body is null. You have to use the code from the Response and if you want to get the data from the error use the errorBody(): public void onResponse(Call<SalaryListModel> call, Response<SalaryListModel> response) { if (response.isSuccessful()) { Log.e(TAG, “onResponse: calling”); if (response.body().getStatus_code() == 200) { Log.e(TAG, … Read more
As you are trying to load Images inside Loop, I would suggest you to implement logic of Lazy loading of Images. Here are some libraries you can give a try: Lazy List Universal Image Loader for Android solved update Main UI Thread or AsyncTask never allowed than where can i update UI thread? [duplicate]
You have to add constraints to your Button in order to make sure that it’s centered on every device. To do this, constrain the button’s left edge to the parent’s left edge, and constrain the button’s right edge to the parent’s right edge. To do this in the layout editor, click and hold on the … Read more
Android Studio includes a debugger that enables you to debug apps running on the Android Emulator or a connected Android device. With the Android Studio debugger, you can do the following: Select a device to debug your app on. Set breakpoints in your Java and C/C++ code. Examine variables and evaluate expressions at runtime. Capture … Read more
Create alternative resources A large part of localizing an app is providing alternative text for different languages. In some cases you also provide alternative graphics, sounds, layouts, and other locale-specific resources. An app can specify many res// directories, each with different qualifiers. To create an alternative resource for a different locale, you use a qualifier … Read more
(Button) is a typecast. Every widget that comes back from findViewById is a View. To treat it as a button, you must explicitly tell the compiler that it is a Button. More information on findViewById here, in the Android documentation: http://developer.android.com/reference/android/app/Activity.html 1 solved What is (button) in android? [duplicate]
Use URLEncoder to encode your URL params such as student_name[k] and roll_no[k]: final String queryString = “student_name=” + URLEncoder.encode(student_name[k], “UTF-8”) + “&roll_no=”+ URLEncoder.encode(roll_no[k], “UTF-8″); Use equals() and not == or != for comparing Strings: if(!””.equals(queryString)) 2 solved running application it’s showing this error in android
Activity A and Activity B, When you move from Activity A to Activity B the lifecycle is as follows Activity A ——————– onCreate() //A onStart() //A onResume() //A – here user can interact with UI(buttons,views), user click button and it moves to second activity onPause() //A ——————– onCreate() //Activity B onStart() //B onResume() //B ——————– … Read more
change your query to this , you’re missing some spaces and also you must remove the last comma from the query @Override public void onCreate(SQLiteDatabase db) { String query = “CREATE TABLE ” + TABLE_PRODUCTS + “(” + COLUMN_ID + ” INTEGER PRIMARY KEY AUTOINCREMENT, ” + COLUMN_PRODUCTNAME + ” TEXT, ” + COLUMN_VENUE + … Read more
email and password should not be null or empty String email = mEmail.getText().toString(); String password = mPassword.getText().toString(); if(email.isEmpty() || password.isEmpty()) return; //you need to display message to the user mAuth.createUserWithEmailAndPassword(email, password) .addOnCompleteListener(CustomerLoginActivity.this, new OnCompleteListener<AuthResult>() { … }) solved App crashes when registration button is pressed
you can do this by checking “yahoo” or “gmail” or … in the string you get from the edit text like this: if (strMessage.contains(“@gmail.com”) || strMessage.contains(“@yahoo.com”){ //Do whatever you want. } 4 solved How to make sure the user type “@yahoo” or”@gmail” in an edit text? [closed]
looks like you have imported the wrong R file is imported R file is of your project or android.R Look and import correct R file that is your package name (com.example.R) 0 solved What is the correct way to declare this?