[Solved] Regex – Allow Alphanumeric, spaces and symbols but CANNOT be only numeric or symbols or spaces. Must have alphabets in it

Introduction Regular expressions, commonly known as “regex” or “regexp”, are special strings used to define search patterns. They are used to match text, and are incredibly powerful and versatile. In this article, we will discuss a particular regex pattern that allows alphanumeric characters, spaces, and symbols, but cannot be only numeric, symbols, or spaces. It … Read more

[Solved] How subquery works?

The query in the parenthesis is called a correlated sub-query. That is because, if you look at the first FROM, it has an alias for the salary table FROM salary a, which in this case is a. The sub-query references the outer query in the WHERE b.salary > a.salary condition, where it checks the condition … Read more

[Solved] Word Guessing Game C++

I’d say most of your problems come down to this line: while(x!=word[i]); As the comments suggest, word is your modified word, not the word list. But also, i is the wrong index. So save the word index you chose earlier: size_t wordIndex = rand() % 17; string word = wordList[wordIndex]; Then change your do loop … Read more

[Solved] Python else condition prints several times

You are always printing something when you are testing, use a temporary variable and print the result after scanning the full list: success = False for i in sheet_data: if (i[0] == “BN”) and (i[1] == “YOU”): found_list.append(i) success = True if success: print(“Success”) else: print(“error”) solved Python else condition prints several times

[Solved] I want to group Columns in pandas [closed]

Try this: uniq_accounts = differenc[‘AccountID’].unique() grped = differenc.groupby(‘AccountID’) ## You can get the grouped data for a certain AccountId like this and store in a dictionary: d = {} for account in uniq_accounts: d[account] = grped.get_group(account) ##Now, dictionary has all accounts data in separate dataframes. You can access like this: for key in d.keys(): print(d[key]) … Read more

[Solved] The function is not being called by browser when you reload the page? What is wrong? [closed]

Try this, Its running var database = [{username: “Sean”, password: 1995}]; var newsFeed = [{username: “Tanya”, timeline: “She says it very cool”}, {username: “Misha”, timeline: “Misha is working at sphere of railways”}]; var askUsernameByPrompt = prompt(“What is your username”); var askPasswordByPrompt = prompt(“What is your password”); function signIn(user, pass){ if(user === database[0].username && pass === … Read more

[Solved] embled if condition in html code and continue with previous div

Your data inside the condition block is not added to anything. You must concatenate to the variable. $custom_column = ‘<div class=”display: table-cell”>’; if(Auth::user()->role_id !== 3){ $custom_column .= ‘<div class=”checkInfo green”> <label class=”chkcontainer”> <input id=”internalCheck’. $entery->id . ‘” onchange=”internalOkFunction(this,’ . $entery->id . ‘);return false;” type=”checkbox” ‘ . $kycinternalok . ‘ > <input id=”hiddenId” type=”hidden” value=”‘.$entery->id.'”> <span … Read more

[Solved] Returning from a function once an async operation is done [duplicate]

Personally, RxJava is overkill. All you need is to pass in the continuation function as a parameter class Validator { void validate(DataListener dl){ DataProvider.getInstance(dl); } And now, wherever you call this method, put in your new DataListener. Don’t assign a result of validate() to a variable solved Returning from a function once an async operation … Read more