You can use box-shadow for this: span { font-size: 50px; font-weight: bold; box-shadow: inset 0 25px 0 white, inset 0 -22px 0 rgba(0,0,0,0.5) } <span>Hello!! How are you</span> 0 solved Add a small background for single line of text [closed]
I see from your post edit last time, value from field datetime like ’20/Mar/2013:03:17:44′. Format from value of datetime can’t convert by a simple way. Try this query: SELECT BASESCORE, [DATEDIFF]= Datediff(second, Min(CONVERT(DATETIME, LEFT(Rtrim(Ltrim(DATETIME)), 11) + ‘ ‘ + RIGHT(Rtrim(Ltrim(DATETIME) ), 8))), Max ( CONVERT(DATETIME, LEFT(Rtrim(Ltrim(DATETIME)), 11 ) + ‘ ‘ + RIGHT(Rtrim(Ltrim(DATETIME)), 8)))) FROM … Read more
.push() returns the new length of the array. [‘one’].push(‘two’); // returns 2 (array length is 2) [‘one’, ‘two’].push(‘something’); // returns 3 (array length is 3) In your case: [].push([]); // array length is 1 where you get array within array. [[]] 0 solved Why does [].push([]) return 1? [duplicate]
If what you want is a division method faster than division by repeated subtraction (which you posted), and that will run indefinitely when you try to divide by zero, you can implement your own version of the Goldschmidt division, and not throw an error when the divisor is zero. The algorithm works like this: 1. … Read more
Your problem is this line subbed = line[-3:] This returns the following: ok\n or il\n Thus, your if statement checking if subbed == ‘ok’ will fail every time. You can fix this by only taking the last two characters, after stripping the newline: subbed = line.strip()[-2:] My original answer didn’t account for reading from a … Read more
There are 3 places where i is changed (after the initialization to 1) Check the comments in order A, B, C, … int main() { int i; for(i=1;i<10;i++) // ^^ 6 -> 7 (end of 1st loop) C // ^^ 10 -> 11 (end of 2nd loop) E { switch(i) { case 1: i=i+2; // … Read more
Here’s a step-by-step breakdown of what your code is doing: int *a; int *b; This declares two pointers to int named a and b. It does not initialize them. That means that their values are unspecified, and you should expect them to be complete garbage. You can think of them as “wild” pointers at this … Read more
This is an initialization of a static array of struct option elements. This structure will have four elements (char*, other, a pointer, and a character), and these are the values. Note the array is ended with a NULL value to prevent searchs throug it to pass beyond end, and note also how some constants relevant … Read more
To do this you can cast the char to an int, int charval = (int) mychar; 5 solved How to print a character code from char*? [closed]
your first question: [i for i in range(n) for j in range(5)] your second question: [j for i in range(k) for j in range(1,6)] where k is the number of repeats 5 solved How to create the following lists with list comprehensions? [closed]
Write a c++ function that will prompt a user for an integer and convert it to binary and print in reverse order [duplicate] solved Write a c++ function that will prompt a user for an integer and convert it to binary and print in reverse order [duplicate]
^ is the binary XOR operator. In short, it converts input into binary numbers and performs a bitwise XOR operation. >>> 2^3 # 10 XOR 11 1 # 01 The expression lone num ^= number is equivalent to lone_num = lone_num ^ number I’d be happy to answer any additional questions you might have. 2 … Read more
That block defines a new trait called Foo, which then allows you to use the trait in various places such as the impl block you have posted. The : Bar part says that any type that implements Foo must also implement the Bar trait. 0 solved Traits and Rust
Here is the java Version private Boolean isDarkTheme(Activity activity) { return (activity.getResources().getConfiguration().uiMode & Configuration.UI_MODE_NIGHT_MASK) == Configuration.UI_MODE_NIGHT_YES; } Java getResources() ->Kotlin resources Java getConfiguration() ->Kotlin configuration Java & ->Kotlin and as you see it’s simple Setters and Getters in koltin are accessed by property name solved Is anyone still using Java? Can I have this translated … Read more
The list comprehension shouldn’t be in the loop, it should be instead of the loop. all_new = [behave[i] for i in range(11) if test[i] == 1] print(all_new) 0 solved How can I put all value in list into same line [closed]