1st : You need to return the response only json data not other data Because you setup the dataType:”json” so comment this line .then ajax will work //print_r($dose); It will work Now. 5 solved Where I am getting wrong?
You have a constructor that takes an IDbTransaction and a Action<UnitofWork> and starts by calling the constructor which takes an IDbTransaction and a Action<UnitofWork>, which is to say itself. That would then immediately call itself, then immediately call itself, then immediately call itself… If it was allowed, then one of two things would happen: It … Read more
It is suggested to use $ in order not to confuse the outer class name with the package name. So $ when you want to refer to an InnerClass and . when referring to the package. For example if Helper is a package name then (lowercase is suggested for package names): <service android:name=”.helper.LocationService”/> where if … Read more
An abstract class is a class that cannot be instantiated and must be extended by child classes. Any abstract methods in an abstract class must be implemented by an extending child class (or it must also be abstract). It’s possible to have an abstract class without abstract methods to be implemented; but that’s not particularly … Read more
use like this it will help String[] subjects = {}; String[] another = {“Physics”,”Chemistry”}; subjects = another.clone(); or second option do like this subjects = Arrays.copyOf(another , another .length); this will copy your another array into your subjects array 5 solved Replacing String array by another [duplicate]
You can still use Math.floor, and simply shift the answer by an order of magnitude: const moreFloor = n => Math.floor (n / 10) * 10 || n; // (or if you prefer…) function moreFloor (n) { return Math.floor (n / 10) * 10 || n; } Just to clarify, the || n at the … Read more
If there is only one var cadena = “I´m from Mexico”.replace(‘`’, ”); To replace all occurrences, use regular expressions: var cadena = “I´m from Mexico”.replace(/`/g, ”); See the JavaScript String.replace method https://developer.mozilla.org/en/docs/Web/JavaScript/Reference/Global_Objects/String/replace solved How to delete or replace ´ in JavaScript? [duplicate]
Something like that: “[-a-zA-ZâÂäÄáàÀÁéèêëÊÈÉÊË’)(ßñÑÇçÌÍìíîïÎÏòóôöÓÔÖÕùúûüÙÚÛÜ]*” 3 solved How to create a C# regex to accept only these characters? [closed]
SELECT cid, SUM(vote) AS upvoted, SUM(CASE WHEN vote = 0 THEN 1 ELSE 0 END) AS downvoted FROM yourtablename GROUP BY cid; 0 solved counting upvotes and downvotes [closed]
On your simulator option goto Hardware->Version->5.1 if 5.1 is not present there, goto Xcode->Preferences->Downloads->iOS 5.1 Simulator->Install Hope this info helps you.. 2 solved Apps not running in ios6 simulator [closed]
It denotes generics. Mapper is a generic and you’re inheriting from Mapper<LongWritable, Text, Text, IntWritable>, which is that generic specialized for those types. It’s like Vector – also a generic – you can have Vector<Object> and Vector<SomeOtherClass>. solved In Java What is the < > notation [duplicate]
Use Unicode Character Properties. /^\P{L}*$/ will match only if there are only non letters from start of the string till the end. \p{L} any kind of letter from any language ==> \P{L} is the negation. Note: Unicode character properties are not supported by all regex flavours. solved Checking a string contains no alpha characters [closed]
If it’s always going to be “NDC: [number]”, you can use a fairly simple Regular Expression. var re = new System.Text.RegularExpressions.Regex(@”NDC\:\s(\d{11})”); var phrase = “Rx: RX15046522B Brand: LEVOTHYROXINE SODIUM Generic: LEVOTHYROXINE SODIUM NDC: 00378180001 Barcode: 0378180001 Strength: 25 mcg Form: Tablet Color: orange Marking: Shape: oblong”; if (re.IsMatch(phrase)) { var match = re.Match(phrase); // entire … Read more
Try this… It will match only reference id /\b(\d{6,20})\b/ check here 6 solved Extract Numeric Value from String Regex PHP [closed]
amount = int(input(“Enter the amount of numbers that you have: “)) numbers = [] for i in range(amount): new = input(‘Enter number {}: ‘.format(i+1)) numbers.append(new) print(numbers) You should probably do some reading on loops in Python. 2 solved Python take a variable number of inputs? [closed]