I have my array as arr=[1,2,3,4]. I pushed an element in it arr.push(5). Now I need to display my array as [5,4,3,2,1]. Any Idea? [duplicate] solved I have my array as arr=[1,2,3,4]. I pushed an element in it arr.push(5). Now I need to display my array as [5,4,3,2,1]. Any Idea? [duplicate]
Give this a try. I assume you’re using a 2D table and not a jagged table. // Assuming a 2D table and not jagged List<List<string>> table = new List<List<string>> { new List<string> { “1”, “2”, “3” }, new List<string> { “1”, “2”, “3” }, new List<string> { “1”, “2”, “3” }, new List<string> { “2”, … Read more
The other answer recommends LINQ, and that is definitely the less verbose way to do it. But I have a feeling that you’re just learning, so may want to have an idea of how this actually works. Below is the an abridged version of the Linq.Sum source code so you can see what is happening. … Read more
For continue, it essentially skips to the end of the loop and starts the next loop, so following through your loop: Look at the current letter If the current letter is a vowel, then continue. (This skips to the next letter in the loop, so the line print(letter) will not be run). If the current … Read more
Use a total variable and add the generated number to the total import random x = 0 total = 0 while x<10: number = random.randrange(1,10) print(number) total += number x=x+1 print(total) 0 solved i’ve generated random numbers. Now i want to add all the numbers that are generated. What is the code to add them … Read more
If I understand correctly, you basically need SUM() of all the Get_val values where either ID_One or ID_Two is 44. Afterwards, you want to display all the unique combinations of ID_One and ID_Two with the “overall sum”. We can get the “overall sum” in a Derived Table; and then CROSS JOIN it back to the … Read more
Here is a possible way: var letters: [Character] = [“a”, “b”, “c”, “d”] let insertionIndex = newArray[0] .index(newArray[0].startIndex, offsetBy: 5) for index in newArray.indices { newArray[index].insert(letters[index], at: insertionIndex) } And you could check the result this way: newArray.forEach { print($0) } Which prints: self.aButton.setTitle(“?”, for: .normal) self.bButton.setTitle(“?”, for: .normal) self.cButton.setTitle(“?”, for: .normal) self.dButton.setTitle(“?”, for: .normal) … Read more
Using sum over countifs would give you what you are looking for. Like for example, assuming you have 200 rows, you may use: =sum(countifs(“A1:A200”,106, “B1:B200″,”EV MEDICAL SERVICES 2019”, “C1:C200”,{“890701″,”890602O”})) Notice the use of curly braces to add a list of comma separated criteria for filtering the last column. 1 solved Count multiple criteria [closed]
“Cannot loop over them”? The classic, traditional iteration over an array is: for (var i = 0; i < arrayLike.length; i++) { doSomethingWith(arrayLike[i]); } This assumption is very deeply ingrained; in fact, arrays are mere plain objects in Javascript with the only addition of the .length property which has specific behaviour when numeric properties are … Read more
The best way to handle this would be: @RequestParam(name=”currency”, defaultValue=”EUR”) String currency or @RequestParam(name=”currency”, required=false) String currency In second case your should check the existance of currency in your in your controller. solved How to handle requests without or with incorrect query parameters [closed]
In C++ functions can be declared inside namespaces. Namespaces are just what its name infer, a collection of names. To access a name (let’s say the function pow()) that is declared inside the namespace std, you can access it in 2 ways: using the namespace access prefix std:: (i.e. std::pow()), or you can declare using … Read more
It’s actually quite simple to do. When your application loads, get a list of the command line variables, then iterate through them and look for the one you want, then act accordingly: Public Sub Main() Dim arguments As String() = Environment.GetCommandLineArgs() For Each a In arguments ‘loop through the args in case there are multiple … Read more
i wrote something, you can compile it online http://cpp.sh/6u447 #include <iostream> int main() { int arr[10] = { 0 }; for(int i=0;i<10;i++){ int temp ; std::cin>>temp; if(temp == 0){ break; } arr[i] = temp; } int sum =0; for(int j=0;j<10;j++){ sum+=arr[j]; } std::cout<<“sum is “<<sum; } 5 solved Sum of 10 number until 0 is … Read more
Welcome to SO. as you know you cannot have same variable name used in a method here is what you need { int AddNumbers(int num1, int num2) //Here’s where the error comes { int result = num1 + num2; return result; } int num2 = 10; int num3 = 20; AddNumbers(num2, num3); } you can … Read more
Else block cannot be kept empty. It must at-least contain ‘pass’. The line ‘print(error)’ must be indented inside the else block. Also your ‘Cmdbar()’ in the elif must be indented. 0 solved “Statement expected” on else but there’s nothing wrong with the code?