I’m not sure if i understood you well but try following code: public class Main { public static void main(String[] argv) { String input = “gudmor,ningeveryone,Have a great day,thankssssssssssss”; String[] firstSplit = input.split(“,”); List<String> result = new ArrayList<>(); String[] tmpArray; for (String elem : firstSplit) { if (elem.length() <= 10) { result.add(elem); } else { … Read more
I think what you want is Control.Leave event or Control.KeyPress or you may also use Control.TextChanged as suggested by @LevZ… Here is some code for Control.Leave Event: TextBoxFirstNumber.Leave += TextBoxFirstNumber_Leave; TextBoxSecondNumber.Leave += TextBoxSecondNumber_Leave; void TextBoxFirstNumber_Leave(object sender, EventArgs e) { if (TextBoxFirstNumber.Text != “” && TextBoxSecondNumber.Text != “”) { TextBoxAnswer.Text = int.Parse(TextBoxFirstNumber.Text) * int.Parse(TextBoxSecondNumber.Text); } } … Read more
You could try: string productPreFix = new string(drpProductIdFix.SelectedValue.ToString() .Take(1).ToArray()); Which will give you an empty string if the drpProductIdFix.SelectedValue.ToString() is an empty string. Or: string productPreFix = drpProductIdFix.SelectedValue != null ? new string(drpProductIdFix.SelectedValue.ToString() .Take(1).ToArray()) : string.Empty; If you need to check that SelectedValue isn’t null as well. solved Converting empty string to Char
Here is one way to do it. You need to get the table object using jquery selector. Then you need to loop the results property of the json data using for keyword. For each object of the result, get the property of subject, date and time_start using property accessor. Create a row string such as … Read more
CGSize size = [theMessage sizeWithAttributes: @{NSFontAttributeName: [UIFont systemFontOfSize:20.0f]}]; Hope it helps… 2 solved sizeWithFont ios 7.0 deprecated [duplicate]
PayPal is indeed setup for this. That’s exactly what the sort of thing they introduced their Adaptive Payments API for back in 2009. You can do what’s called a delayed chained payment, which is where the buyer will submit the payment, and all the money will go to a primary receiver. The money will stay … Read more
No, you can use the default emulator or other tools like Genymotion. You should just consider that a real device might be handy as you get a better feeling of your app when you have it on a real device. Also there are limitations based on the emulator you use. For example the graphic power … Read more
Not sure about your problem. But from the code you given i just added some changes. Try this. html { background-image: url(file:///C:/Users/Tom/Pictures/93af2cd5d83f6f839db98e6d5079b4f4.jpg); } h1 { color: gray; } a:visited { color: black; } a:hover { color: yellow; } a:active { color: yellow; } a { background-color:gray; filter:alpha(opacity=60); opacity:0.4; padding:0px 15px; } 8 solved How do … Read more
Using PHP, you can redirect the user after handling the submitted data: // After handling submitted data, redirect: header(“Location: new-page-here.php”); This is actually recommended, as it stops the user re-submitting the data if they refresh the page. As per the instructions for header(), do not echo any HTML before it. This includes whitespace before your … Read more
//Initiate new array to store coords $latlongs = array(); //Loop through your array foreach($yourArray as $k=>$v){ // Loop through the partnerlist to extract lat/lon // Append to your coord array, and preserve the industry key // So that you know which lat/lons came from where foreach($v[‘partnerlist’] as $a){ $latlongs[$k][] = array(“latitude”=>$a[‘latitude’],”longitude”=>$a[‘longitude’]; } } This will … Read more
startActivityForResult AND onActivityResult have [int requestCode] in paramters. Use requestCode to determine which editText is handling and fill text for it Call another activity: startActivityForResult(newActivity, requestCode); When result is returned: @Override protected void onActivityResult(int requestCode, int resultCode, Intent data) { // TODO Auto-generated method stub switch (requestCode) { case 1://working with first edit text //fill … Read more
first of all stop using return from event handler. convert your code to <form … onsubmit=”validate(event,this)”> change your function to validate(event,form); wherever you feel form should not be submitted.. write : event.preventDefault() instead of return false Demonstration : http://codepen.io/anon/pen/kGmeL 7 solved Why validation for password field validation not working?
I made you a page that switches between two images in a random manner. You can easily expand this, by adding image urls to the images array <!DOCTYPE html> <html> <head> <script type=”text/javascript”> var p = { onload: function() { setInterval(p.switchImage, 10000); }, switchImage: function() { document.getElementById(“image”).src = p.images[Math.floor(Math.random() * p.images.length)]; }, images: [“http://www.schoolplaten.com/afbeelding-hond-tt20990.jpg”, “http://www.schoolplaten.com/afbeelding-hond-tt19753.jpg”] … Read more
You should take a look at this extension https://github.com/StickSports/ANE-Can-Open-URL It’s quite old and it might not work as expected, but is worth a shot. 1 solved check if an air android app is installed on the mobile
You can use String‘s methods replaceAll and split together here. String one = “show ip interface brief | include 1234**\n Gi1/23.1234 xxx.225.xxx.106 YES manual up up”; String[] tokens = one.replaceAll(“[^\\n]+\\n\\s*”, “”).split(“\\s+”); System.out.println(Arrays.toString(tokens)); Output [Gi1/23.1234, xxx.225.xxx.106, YES, manual, up, up] solved How to split a string if any chracter is found in java