Declare a variable to count the stars with an appropriate data type. Iterate (loop) over the string to check each character for equality with ‘*’. If this is the case then increment your star counter. Width and height are not required. If you want to constrain a larger field to the width and height provided, … Read more
Just Close this excel file: EtatServ-85101-23032019.xls 0 solved How can I fix java.io.FileNotFoundException in java? [closed]
You are missing something here. You have a List of Strings, and you should iterate over the characters of each of these Strings separately in order to convert it to an int. This means you need two nested loops. Though there are much easier ways of doing it (with Integer.parseInt()), here’s an implementation based on … Read more
As said in remarks scanf(“%s%c”,a[i],&ch); try to read a ‘word’ as a string in a[i] and a char in ch Because a ‘word’ is ended by a separator and there is no space between %s and %c if a character is read to set ch that character is the first separator Example : #include <stdio.h> … Read more
67% = 67/100 = 0.67 So new_price = old_price * Discount_in_percent/100 solved How Can I calculate value by percentage in python? [closed]
I would use regex… var name = Regex.Match(File.ReadAllText(filename), @”Member:[ \t\r\n]+(.+?)\r?\n”) .Groups[1].Value; 0 solved Read data from varying positions in a text file [closed]
You can use Regex.Matches(): string source = “Mobile: +49 (123) 45678Telephone: +49 (234) 567890Fax: +49 (345) 34234234”; string[] phones = Regex .Matches(source, “[A-Za-z]+: \\+([0-9)( ])+”) .Cast<Match>() .Select(i => i.ToString()) .ToArray(); OR You can use IndexOf(): string source = “Mobile: +49 (123) 45678Telephone: +49 (234) 567890Fax: +49 (345) 34234234”; var telephoneIndex = source.IndexOf(“Telephone”, StringComparison.InvariantCulture); var faxIndex … Read more
If i understood it right, you want to achieve the requirements by using the program you wrote above. It possible to re-design it using your own code. eg : For get() struct node *get(int key, void *data) { if(*head_ref != NULL) { key = *head_ref->data; return *head_ref; } else { printf(“Error in retrieving data from … Read more
A few ways to do this. String replace, as mentioned by Ashish. $input = “-**abcd1234-*—“; $output = str_replace(array(‘-‘, ‘*’), ”, $input); echo $output; If you have a large number of characters to strip though, maybe this would be a little easier. $input = “-**abcd1234-*—“; $remove = “-*”; $output = str_replace(str_split($remove), ”, $input); echo $output; And … Read more
Introduction The preg_replace/string_replace symbol – or * to space is a useful tool for replacing certain symbols with a space in a string. This can be useful for formatting text, removing unwanted characters, or making a string easier to read. This tutorial will explain how to use the preg_replace/string_replace symbol – or * to space … Read more
You have to pass parameter between two pages So first of all your have to edit add link on it <?php try { $pdo = new PDO(‘mysql:host=localhost;dbname=informal’,’vad’,’6989′); $pdo->setAttribute(PDO::ATTR_ERRMODE,PDO::ERRMODE_EXCEPTION); $pdo->exec(‘SET NAMES “utf8″‘); } catch(PDOException $e) { echo $e->getMessage(); } $sql=”SELECT title,content FROM postID”; $result = $pdo->query($sql); while($row = $result->fetch()) { echo “<a href=anotherpage.php?id=”.$row[‘id’].”>”.$row[‘title’] . “</a><br />”; … Read more
Searching for a single item in an array is O(N) Searching for a longest run of increasing numbers in an array is O(N^2) if you use a straightforward algorithm with two nested loops* Note: This is not Java-specific. * A faster algorithm exists to do this search. solved Java Search algorithm [closed]
Basically, when a user clicks on one of the invites, they are sent to your application’s canvas URL. The one you set in your application’s settings. The user will be sent to your application and from there you can redirect them to your actual site using a JavaScript redirect as they do in the tutorial … Read more
I think there is a bit of a confusion here what the string concatenation does to your values. It is nothing less than simply using the default format for a parameterless ToString()! Each of your strings like Debug.Log(“currentTime: ” + currentTime); basically internally implicitly equal Debug.Log(“currentTime: ” + currentTime.ToString()); In that case the ToString() without … Read more
How do I register a Pivotal Cloud Foundry Service Broker to make it accessible from multiple spaces within the same Organization, if I have Org-level permissions? I don’t think you can do this. You’d need to be a platform admin/operator. Then you’d need to register the service broker with the platform & mark that broker … Read more