I don’t have the commenting privilege yet, but this is a duplicate. This question could be found from a quick Google: Splitting a string into two halfs int mid = length / 2; //get the middle of the String String[] parts = {text.substring(0, mid),text.substring(mid)}; solved How to split a string into two equally based on … Read more
It’s not asynchronous. You need to invoke start() not run() Run will execute the Runnable’s run method in the current thread. start will create a new thread which will invoke the run method. 0 solved Java Thread Hang
You have a cycle in your header inclusion: MainProgram.h includes FileMgr.h FileMgr.h includes MgrBase.h MgrBase.h includes MainProgram.h You need to break this cycle using forward declarations. The rule in header files should be: if you only need to declare reference or pointer to a type X, forward declare X instead of including the header which … Read more
Change the first format to SimpleDateFormat tempFormat = new SimpleDateFormat(“yyyy-MM-dd”); as DD is the day in the year. 22 is definitely in January 0 solved simple date format giving wrong month [duplicate]
A more elegant solution : if( [“CheckBox”, “Radio-Button”, “Payment-Gateway”, “Message”, “Award”].indexOf(data) == -1){ // data isn’t any of these words } else { // data is one of these words } 1 solved what is wrong with this IF satemenet [closed]
You need just to add the variable name in front of the properties. a.data.clients[1].name=”Johny”; If you have a string, you could split the path and reduce the path by walking the given object. If no Object exist, create a new property with the name, or an array. Later assign the value. function setValue(object, path, value) … Read more
The first piece of code assigns the character ‘1’, which has an ASCII value of 49. Printing this as a character will yield 1, while printing as a number will yield 49. The second piece of code assigns the value 1. Printing it as a character yields an unprintable character with an implementation defined representation, … Read more
erm… you can’t really do that with html alone, mate. You need a server-side script to handle that. Suggest Php. After that, use a GET or POST method to carry your like or dislike vote to the server-side script. solved How to implement the dislike-like button [closed]
tl;dr: the key paths you are looking for are “length” and “self” (or “description” or “uppercaseString” depending on what how you want to compare) As you can see in the documentation for NSSSortDescriptor, a sort descriptor is created “by specifying the key path of the property to be compared”. When sorting string by their length, … Read more
That’s an invalid “object”. It is supposed to be an array with []. If that’s how your server is giving, you have to change the response there. In case, if you can’t do that, you may parse it right in JavaScript. var keyword = ‘{“coconut sugar”, “healthy and natural sweetener”, “low glycemic index sweetener”}’; keyword … Read more
You cannot get any Facebook’s User data using the Facebook API without the User’s explicit permission. The permission is granted to you (your APP) by the user in a popup window stating exactly what information you are receiving and with which permission type (read, write etc..) This is all for good reasons. 7 solved Get … Read more
Using XMLHttpRequest var r = new XMLHttpRequest(); r.open(‘GET’, ‘csv_data.csv’); r.onreadystatechange = function () { if (r.readyState != 4 || r.status != 200) return; successFunction(r.responseText); }; r.send(); Haven’t tested it. solved How do I convert jQuery AJAX code to vanilla JavaScript? [duplicate]
You really should clarify the issue you’re having; feel free to read How to Ask. Basic Loop As far as your question states (from my understanding), you would like to repeatidly call a method and have that method return the index of a string that corresponds to the current call. I would look into the … Read more
This will do what you need, though you might want to tweak it to fit your project. <?php $date=”01-Aug-2018″; $date2 = ’07-Aug-2018′; $period = new DatePeriod( new DateTime($date), new DateInterval(‘P1D’), new DateTime($date2) ); $weekends = []; foreach ($period as $key => $value) { if ($value->format(‘N’) >= 6) { $weekends[$value->format(‘d-m-Y’)] = $value->format(‘D’); } } var_dump($weekends); 1 … Read more
Add an id to your footer. <div id=’myFooter’ …> Make the user click on a <a> like below, <a href=”#myFooter”/> Click here for an example 2 solved How do i code so that my button after clicking will direct user to the footer in the same html? [closed]